Answer:
The answer is
<h2>90 km</h2>
Explanation:
To find the distance covered by an object given it's velocity and time taken , we use the formula
<h3>distance = velocity × time</h3>
From the question
velocity = 30 km/hr
time = 3 hrs
The distance covered is
distance = 30 × 3
We have the final answer as
<h3>90 km</h3>
Hope this helps you
Answer:
U = 4 U₀
we see that the gecko must use 4 times more energy to double the force
Explanation:
For this exercise they indicate that we can approximate the situation to a charged capacitor, so the stored energy is
U = Q² / 2C
where C is the capacitance that does not change since it is the same gecko and Q is the stored charge. In the initial state
U₀ = Q₀² /2C
They tell us that the load is doubled
Q = 2Q₀
where Qo is the initial charge; the new energy is
U = (2Q₀)² / 2C
U = 4 Q₀² / 2C
U = 4 U₀
where U₀ is the initial energy
Therefore we see that the gecko must use 4 times more energy to double the force
Answer:
1.5 x 10¹⁸hz
Explanation:
Given parameters:
Wavelength = 2 x 10⁻¹⁰m
Unknown:
Frequency = ?
Solution:
To find the frequency, use the expression below;
V = f x wavelength
V is the speed of light = 3 x 10⁸m/s
f is the frequency
Now;
Insert the parameters
3 x 10⁸ = 2 x 10⁻¹⁰ x frequency
Wavelength = = 1.5 x 10¹⁸hz
Answer:
Seven
Explanation:
Because all halogens have seven valence electrons, they are “eager” to gain one more electron. Doing so gives them a full outer energy level, which is the most stable arrangement of electrons. Halogens often combine with alkali metals in group 1 of the periodic table.
Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg