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3 years ago

If a substance has a volume of 30ml and a mass of 6 grams, what is its density?

Chemistry

1 answer:

fredd [130]3 years ago

6 0

0.2 is the correct answer and shown above is the shown work

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6.50 g of a certain Compound x, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 1

gayaneshka [121]

Answer:

$C_{10}H_8$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to find the molecular formula of the given compound by firstly calculating both moles and grams of carbon in carbon dioxide and hydrogen in water, as the only sources of these elements derived from the compound x due to its combustion:

$n_C=22.35gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.51molC\\\\m_C=0.51molC*\frac{12.01gC}{1molC} =6.10gC$

$n_H=3.66gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}=0.41molH\\\\m_H=0.41molH*\frac{1.01gH}{1molH}=0.41g$

Now, since the addition of carbon and hydrogen is about 6.50 grams, we infer the compound has no oxygen, that is why we now set the mole ratios in the empirical formula for both C and H as shown below:

$C:\frac{0.51mol}{0.41mol}= 1.24\\\\H:\frac{0.51mol}{0.51mol}= 1\\\\C_{1.24}H$

Yet it cannot be decimal, that is why we multiply by 4 to get the correct whole-numbered empirical formula:

$C_5H_4$

Whose molar mass is 64.09 g/mol, which makes the ratio of molar masses:

$\frac{128.g/mol}{64.09g/mol} =2$

Therefore, the molecular formula is twice the empirical one:

$C_{10}H_8$

Regards!

8 0

3 years ago

The periodic table organizes elements according to INCREASING

jeyben [28]

C would be the correct answer

5 0

3 years ago

Read 2 more answers

How many moles of pcl5 can be produced from 23.0 g of p4 (and excess cl2)? express your answer to three significant figures and

NeX [460]

Balance Chemical equation is,

P₄ + 10 Cl₂ → 4 PCl₅

According to Balance Equation,

123.89 g (1 mole) of P₄ reacts to produce = 4 Moles of PCl₅
Then,
23 g of P₄ will react with excess Cl₂ to produce = X moles of PCl₅

Solving for X,
X = (4 mol × 23 g) ÷ 123.89 g

X = 0.742 g of PCl₅
Result:
When 23 g of P₄ is reacted with excess Cl₂, 0.742 g of PCl₅ is produced.

4 0

4 years ago

How much salt is required to make 250g of a 5.0% saline solution?

Harlamova29_29 [7]

Answer:

do you have notes for this if I saw an example I might know the answer

3 0

4 years ago

Please help thankyou

dangina [55]

Hope this serves helpful to u!!

Hope this helps by the way as well

Good luck!!!

6 0

3 years ago