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Luba_88 [7]
3 years ago
7

A 0.25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. What is the final veloc

ity of the combined mass
Physics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:20/47 meter per second

Explanation:

Mass of arrow(ma)=0.25kg

Velocity of arrow(va)=12m/s

Mass of target(mt)=6.8kg

Velocity of target(vt)=0 since target is at rest

Conservation of linear momentum says that :

maxva+mtxvt=(ma+mt)V

V=(maxva+mtxvt)/(ma+mt)

V=(0.25x12+6.8x0)/(0.25+6.8)

V=3/(7.05)

V=20/47 meter per second

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3 years ago
Calculate the amount of heat liberated (in kj) from 411 g of mercury when it cools from 88.0°c to 12.0°c.
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Pete Zaria works on weekends at Barnaby's Pizza Parlor. His primary responsibility is to fill drink orders for customers. He fil
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Answer:

W_n_e_t=7.648512 \approx 7.6J

K.E=0.8J

v=0.7844645406 \approx 0.78m/s

Explanation:

From the question we are told that

Mass of pitcher   M= 2.6kg

Force on pitcher f=8.8N

Distance traveled 48cm=>0.48m

Coefficient of friction \mu=0.28

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F=\mu N

F=0.28*2.6*9.8

F=7.1344N

Generally work done on the pitcher is mathematically given as

W_n_e_t=W_f+W_F

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K.E= W_n_e_t

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0.8=1/2mv^2

Velocity as subject

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v=\sqrt{\frac{0.8*2}{2.6} }

v=0.7844645406 \approx 0.78m/s

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