Explanation:
The given data is as follows.
Fluid is water so, density
Weight flow rate = 500 lbf/s = 2224.11 N/sec
Cross-sectional area (A) =
= 0.05184
Hence, weight flow rate will be given as follows.
w =
2224.11 N/sec =
V = m/s
= 4.373 m/s
Thus, we can conclude that average velocity in the given case is 4.373 m/s.
Answer:
534.9 N
Explanation:
The skier weight is his mass times gravitational acceleration g
W = mg = 103 * 9.8 = 1009.4 N
This weight can be divided into 2 components, one perpendicular and the other parallel to the 32-degree slope. The parallel component would equal to
According to Ideal gasTo solve this problem, the fastest relationship allows us to observe the proportionality between the two variables would be the one expressed in the ideal gas equation, which is
Here
P = Pressure
V = Volume
N = Number of moles
R = Gas constant
T = Temperature
We can see that the pressure is proportional to the temperature, then
This relationship can be extrapolated to all the scenarios in which these two variables are related. As the pressure increases the temperature increases. The same goes for the pressure in the atmosphere, for which an increase in this will generate an increase in temperature. This variable can be observed in areas of different altitude. At higher altitude lower atmospheric pressure and lower temperature.