3 years ago

2. A mass-spring system oscillates with a frequency of 20 Hz. What is the period?

Physics

1 answer:

Alex_Xolod [135]3 years ago

5 0

Answer:

0.05s

Explanation:

f=20Hz

we know,

time period=t=1/f

t=1/20

=0.05s

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The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 m

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Answer:

0.0360531138247 V/m

Explanation:

$\rho$ = Resistivity of gold = $2.44\times 10^{-8}\ \Omega .m$ (General value)

I = Current = 940 mA

d = Diameter = 0.9 mm

A = Area = $\dfrac{\pi}{4}d^2$

E = Electric field

Resistivity is given by

$\rho=\dfrac{EA}{I}\\\Rightarrow E=\dfrac{\rho I}{A}\\\Rightarrow E=\dfrac{2.44\times 10^{-8}\times 940\times 10^{-3}}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}\\\Rightarrow E=0.0360531138247\ V/m$

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What's the time constant of a 10 H inductor and a 200 ohm resistor connected in series

melamori03 [73]

<h3>Option B</h3><h3>The time constant of a 10 H inductor and a 200 ohm resistor connected in series is 50 millisecond</h3>

<em><u>Solution:</u></em>

Given that,

10 H inductor and a 200 ohm resistor connected in series

To find: time constant

<em><u>The time constant in seconds is given as:</u></em>

$Time\ constant = \frac{L}{R}$

Where,

L is the inductance in henry and R is the resistance in ohms

$Time\ constant = \frac{10}{200}\\\\Time\ constant = 0.05\ seconds$

Convert to millisecond

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