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Rudik [331]
3 years ago
11

Which statement is TRUE about oxidation-reduction reactions? a. Every oxidation must be accompanied by a reduction. b. There are

four commonly accessed oxidation states of carbon. c. Dehydrogenases typically remove two electrons and two hydrides. d. They usually proceed through homolytic cleavage. e. During oxidation a compound gains electrons.
Chemistry
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

Every oxidation must be accompanied by a reduction.

Explanation:

Oxidation and reduction are complementary processes. There can be no oxidation without reduction and vice versa. It is actually a given an take affair. A specie looses electrons which must be gained by another specie to complete the process. This explains why the selected option is the correct one.

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What's the pH of a solution with a concentration of hydronium ions of 5.29x10^-10?
romanna [79]
C. 5.29 should be the answer
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The caloric content of 0.50 cup of cottage cheese is 1.10 x 102 kcal. This is the amount of energy released when 0.50 cup of cot
V125BC [204]

Answer:

A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.

What is the specific heat of the substance?

If it is one of the substances found in Table 8.1.1, what is its likely identity?

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3 years ago
Air contains nitrogen, oxygen, argon, and trace gases. Ifthe partial pressure of nitrogen is 592 mm Hg, oxygen is160 mm Hg, argo
Katena32 [7]

Answer:

760 mmHg

Explanation:

Step 1: Given data

  • Partial pressure of nitrogen (pN₂): 592 mmHg
  • Partial pressure of oxygen (pO₂): 160 mmHg
  • Partial pressure of argon (pAr): 7 mmHg
  • Partial pressure of the trace gas (pt): 1 mmHg

Step 2: Calculate the atmospheric pressure

Since air is a gaseous mixture, the atmospheric pressure is equal to the sum of the gases that compose it.

P = pN₂ + pO₂ + pAr + pt = 592 mmHg + 160 mmHg + 7 mmHg + 1 mmHg = 760 mmHg

6 0
3 years ago
Carbon dioxide in the atmosphere dissolves in raindrops to produce carbonic acid (H2CO3), causing the pH of clean, unpolluted ra
anastassius [24]

Answer:

The range of [H⁺] is from 2.51 x 10⁻⁶ M to 6.31 x 10⁻⁶ M,

Explanation:

To answer this problem we need to keep in mind the <u>definition of pH</u>:

  • pH = -log [H⁺]

So now we <u>calculate [H⁺] using a pH value of 5.2 and of 5.6</u>:

  • 5.2 = -log [H⁺]

-5.2 = log [H⁺]

10^{-5.2} = [H⁺]

6.31 x 10⁻⁶ M = [H⁺]

  • 5.6 = -log [H⁺]

-5.6 = log [H⁺]

10^{-5.6} = [H⁺]

2.51 x 10⁻⁶ M = [H⁺]

6 0
3 years ago
PLEASE HELP ME ASAP What is the volume of 28.9 g of mercury if the density is 13.8 g/mL? *
strojnjashka [21]

Answer:

2.09 mL

Explanation:

density = mass/volume

13.8 = 28.9/v

13.8v = 28.9

v = 2.09 mL

8 0
3 years ago
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