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zzz [600]
2 years ago
14

Calculate the volume occupied by 16.3 moles of nitrogen gas at 273 K and 101.3kPa

Chemistry
1 answer:
erma4kov [3.2K]2 years ago
8 0

Answer: V= 366.3 L

Explanation:

Using the ideal gas law; PV = nRT

P= pressure = 101 kPa  , n =  Number of moles = 16.3 moles

V = Volume = ?               R= Gas constant =  8.31 kPa L/Mol K

T= Temperature = 273K

We make ''V'' the subject of the formular;

V = n R T/ P =  16.3mol  x 8.31 kPa. L / mol. K x 273 K

                        -----------------------------------------------------

                                           101 kPa

                V  = 366.3 L

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A compound containing sodium, chlorine, and oxygen is 25.42% sodium by mass. A 3.25 g sample gives 4.33×1022 atoms of oxygen. Wh
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= ( 4.33  x  10^ 22 x 1 mole )  /  6.02  10^23=   0.0719 moles
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step  3
calculate the  moles   of  each  element
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blagie [28]
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6 0
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Answer:

Option (c).

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