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Anastasy [175]
3 years ago
15

If you hit a wall, will the force that you exert on the wall be greater than, or less than, or equal to the force that the wall

exerts on you. Explain your answer.
Physics
1 answer:
leva [86]3 years ago
5 0
I think this would have to be equal because the wall is not moving away from or into your hit so therefore your force is just as equal as the walls force
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A trait that can only be inherited by a female would be a
Talja [164]
The trait that a female alone would inherit would be certain hormones that are involved in reproduction. AND, for the obvious answer who some people just HAVE to mention, "Look in your pants and tell me what you see." I would also appreciate if you let my gender be unknown.
6 0
4 years ago
3. Two charged boxes are 4 meters apart from each other. The blue box has a charge of +0.000337
adelina 88 [10]

Answer:

Charge on the red box is -0.0033 C as it is attracting the blue box

Explanation:

As we know that two boxes are attracting each other

So here we can say that two boxes will have opposite charges

So as we know that electrostatic force between two charges is given as

F = \frac{kq_1q_2}{r^2}

here we have

here we know that

k = 9 \times 10^9

q_1 = 0.000337 C

r = 4 m

F = 626 N

626 = \frac{(9\times 10^9)(0.000337)q}{4^2}

q = 0.0033 C

7 0
3 years ago
To measure the height of the cloud cover at an airport, a worker shines a spotlight upward at an angle 75° from the horizontal.
Yuri [45]

Answer: The height of the cloud = 394.55 m

Explanation:

The observer is 500m away from the spotlight.

Let x be the distance from the observer to the interception of the segment of the height, h with the floor. The equations are thus:

Tan 45° = h/x ... eq1

Tan 75° = h/(500- x ) ... eq2

From eq 1, Tan 45° = 1, therefore eq1 becomes:

h = x ... eq3

Put eq3 into eq2

Tan 75° = h/(500- h)

h = ( 500 - h ) Tan 75°

h = 500Tan 75° - hTan75°

h + h Tan 75° = 500 Tan 75°

h ( 1 + Tan 75° ) = 500 Tan75°

h = 500Tan75°/ (1 + Tan 75°)

h= 1866.02 / 4.73

h = 394.55m

4 0
3 years ago
Two fans are watching a baseball game from different positions. One fan is located directly behind home plate, 18.3 mfrom the ba
hjlf

Answer:

Δt = 0.315s

Explanation:

To calculate the time difference, in which both fans hear the batterstrike, you first calculate the time which takes the sound to travel the distances to both fans:

t_1=\frac{d_1}{v_s}

t_2=\frac{d_2}{v_s}

d1: distance to the first fan = 18.3 m

d2: distance to the second fan = 127 m

vs: speed of sound = 345 m/s

You replace the values of the parameters to calculate t1 and t2:

t_1=\frac{18.3m}{345m/s}=0.053s\\\\t_2=\frac{127m}{345m/s}=0.368s

The difference in time will be:

\Delta t =t_2-t_2=0.368s-0.053s=0.315s

Hence, the time difference between hearing the sound at the location s of both fans is 0.315s

4 0
3 years ago
A(n) _____ is a gap in the geologic record where some rock layers have been lost because of erosion.
Elenna [48]
I'm not sure, I think it's option A.

Let me know if I'm wrong!
4 0
4 years ago
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