Answer:
T = 0.003 s
(Period is written as T)
Explanation:
Period = time it takes for one wave to pass (measured in seconds)
frequency = number of cycles that occur in 1 second
(measured in Hz / hertz / 1 second)
Period : T
frequency : f
So, if we know that the frequency of a wave is 300 Hz, we can find the period of the wave from the relation between frequency and period
T =
f = ![\frac{1}{T}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BT%7D)
to find the period (T) of this wave, we need to plug in the frequency (f) of 300
T = ![\frac{1}{300}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B300%7D)
T = 0.00333333333
So, the period of a wave that has a frequency of 300 Hz is 0.003 s
[the period/T of this wave is 0.003 s]
The correct answer to this is (A. Units Only).
It shows that there is a velocity of 35, but the units are missing.
Answer: Boyle found that when the pressure of a gas at a constant temperature is increased, the volume of the gas decreases. When the pressure of a gas is decreased, the volume increases. This relationship between pressure and volume it's called Boyle's law.
Explanation: In the 1600s, Boyle measured the volumes of gases at different pressures. Boyle found that when the pressure of a gas at a constant temperature is increased, the volume of the gas decreases. When the pressure of a gas is decreased, the volume increases. This relationship between pressure and volume it's called Boyle's law.
Answer:
![V=\dfrac{3}{2}\ m/s](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B3%7D%7B2%7D%5C%20m%2Fs)
Explanation:
Two identical bodies are sliding toward each other on a frictionless surface.
Initial speed of body 1, m₁ = 1 m/s
Initial speed of body 2, m₂ = 2 m/s
They collide and stick.
We need to find the speed of the combined mass. Let V is the speed of the combined mass.
Using the conservation of momentum.
![m_1u_1+m_2u_2=V(m_1+m_2)](https://tex.z-dn.net/?f=m_1u_1%2Bm_2u_2%3DV%28m_1%2Bm_2%29)
We have, m₁ = m₂ = m
![m\times 1+m\times 2=(m+m)V\\\\m+2m=2m\times V\\\\3m=2mV\\\\V=\dfrac{3}{2}\ m/s](https://tex.z-dn.net/?f=m%5Ctimes%201%2Bm%5Ctimes%202%3D%28m%2Bm%29V%5C%5C%5C%5Cm%2B2m%3D2m%5Ctimes%20V%5C%5C%5C%5C3m%3D2mV%5C%5C%5C%5CV%3D%5Cdfrac%7B3%7D%7B2%7D%5C%20m%2Fs)
So, the speed of the combined mass is
.