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3 years ago

A 2 L container contains 5 moles of helium gas at 0.5 atm. What is the temperature of the gas?

Chemistry

1 answer:

lara [203]3 years ago

7 0

Answer:

2.44 K IS THE TEMPERATURE OF THE GAS

Explanation:

PV = nRT

P = 0.5 atm

V = 2 L

n = 5 moles

R = 0.082 L atm mol^-1 K^-1

T = ?

Substituting for T in the equation, we obtain:

T = P V / nR

T = 0.5 * 2 / 5 * 0.082

T = 1 / 0.41

T = 2.44 K

The temperature of the gas is 2.44 K

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What is the concentration of a solution which is 2g in 150cm3 in g/dm3

Irina-Kira [14]

Answer:

13.33 g/dm³

Explanation:

Concentration (g/dm³)= mass(g) ÷ volume (dm³)

Now you need to convert 150 cm³ to dm³

1000cm³ = 1 dm³

thus, 150 cm3= 150 ÷ 1000

= 15dm³

and you already have mass in grams

so concentration = 2 ÷ 0.15

= 13.33 g/dm³ and there you go.. solved ;)

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2 years ago

Zinc reacts with excess hydrochloric acid to produce zinc chloride and hydrogen gas. What happens to the reaction rate if you in

agasfer [191]

The correct response I believe is D. The reaction rate increases because the probability of collisions increases as there are more Zn atoms to react.

4 0

3 years ago

Read 2 more answers

The mass and volume of each box is given in the chart below. Calculate the density of each box. Density = Mass/ volume which box

stira [4]

Box C will have the greatest density.

All boxes have the same volume.

Explanation:

We calculate the density using the following formula:

density = mass / volume

density of Box A = 10 g / 20 cm³ = 0.5 g/cm³

density of Box B = 30 g / 20 cm³ = 1.5 g/cm³

density of Box C = 170 g / 20 cm³ = 8.5 g/cm³

Box C will have the greatest density.

All boxes have the same volume.

Learn more about:

density

brainly.com/question/952755

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7 0

2 years ago

The first excited vibrational energy level of diatomic chlo- rine (Cl2) is 558 cm^-1 above the ground state. Wave- numbers, the

Usimov [2.4K]

Answer:

The answer is "0.0000190 and 2.7 J".

Explanation:

$\to P_4=\frac{e^{-\beta}(4+\frac{1}{2}) hev}{2vb}\\\\$

$=\frac{e^{-9(1.35)}}{0.278v}\\\\=\frac{e^{-12.5}}{0.278}\\\\=\frac{0.000005285}{0.278}\\\\=0.0000190$

Given:

$h=6.626 \times 10^{-34}\\\\c=3\times 10^{10}\\\\v=558\ cm^{-1}\\\\K=1.38 \times 10^{-23}\\\\ T=298\\\\$

$E=\frac{hcv}{KT}\\\\$

by putting the value into the above formula so, the value is 2.7 J

6 0

3 years ago

Answer now pls and i give you mega points ;)

astraxan [27]

HCl is an acid
C5H5N is a base
Cl- is a base
HC5H5N+ is an acid

7 0

2 years ago