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Pie
2 years ago
13

What is the significance of the Roman Numeral when naming binary ionic compounds?

Chemistry
1 answer:
serious [3.7K]2 years ago
8 0

Answer:

Roman numbers are oxidation state of the metals

Because some elements of metals show more than one oxidation state like iron Fe2+ in ferrous and Fe3+ in ferric.

Explanation:

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Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea
REY [17]

Explanation:

Mg(s) + Cr(C2H3O2)3 (aq)

Overall, balanced molecular equation

Mg(s) + Cr(C2H3O2)3(aq) --> Mg(C2H3O2)3(aq) + Cr(s)

To identify if an element has been reduced or oxidized, the oxidation number is observed in both the reactant and product phase.

An increase in oxidation number denotes that the element has been oxidized.

A decrease in oxidation number denotes that the element has been reduced.

Oxidation number of Mg:

Reactant - 0

Product - +3

Oxidation number of Cr:

Reactant - +3

Product - 0

Note: C2H3O2 is actually acetate ion; CH3COO- The oxidatioon number of C, H and O do not change.

Oxidized : Mg

Reduced : Cr

7 0
3 years ago
Asking high school students if the school day should be lengthened to improve
Alla [95]

Answer:

it can be tooo. long or coplicated because nomatter how long u stay in school they give u homework and also a lot of people have jobs when would they be ableto work

Explanation:

3 0
3 years ago
Read 2 more answers
How many atoms are in .800 g of Ca
Goshia [24]
The answer for this question is 0.8
8 0
3 years ago
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Suppose 0.981 g of iron (II) iodide is dissolved in 150. mL of a 35.0 m M aqueous solution of silver nitrate. Calculate the fina
yaroslaw [1]

Answer:

Final molarity of iodide ion C(I-) = 0.0143M

Explanation:

n = (m(FeI(2)))/(M(FeI(2))

Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol

So n = 0.981/309.85 = 0.0031 mol

V(solution) = 150mL = 0.15L

C(AgNO3) = 35mM = 0.035M = 0.035m/L

n(AgNO3) = C(AgNO3) x V(solution)

= 0.035 x 0.15 = 0.00525 mol

(AgNO3) + FeI(3) = AgI(3) + FeNO3

So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol

C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M

8 0
3 years ago
It takes 90 N of force to lift a box of books off my smiths table. If you can only leave the box 25% of the way up, how many new
leva [86]

Answer:3.6 I think sorry if wrong

Explanation:

90 divided by 25

4 0
2 years ago
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