Suppose that an ideal transformer has 400 turns in its primary coil and 100 turns in its secondary coil. The primary coil is con
nected to a 120 V (rms) electric outlet and carries an rms current of 10 mA. What are the rms values of the voltage and current for the secondary?
1 answer:
To solve this problem we need to use the induced voltage ratio law with respect to the number of turns in a solenoid. So

For the given values we have to



Replacing we have that,


Therefore the RMS value for secondary is 30V.
The current can be calculated at the same way, but here are inversely proportional then,

Replacing we have


Therefore the rms value of current for secondary is 40mA
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Hi, what is it you need help with?
Answer:
goverment
Explanation:
It is a solenoid.
The coil of wire looks like a spring and inside of it is a magnetic field
Answer:
Explanation:
A. Q= It
30E-3A=q
Ne = q
30E-3/1.6*10-19= N
N= 1.8*10^16 electrons
B. Power= I x v
= 30*10^-3A x 100*10^3v
= 3000watts
B If you want me to explain then ask