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HACTEHA [7]
3 years ago
14

Suppose that an ideal transformer has 400 turns in its primary coil and 100 turns in its secondary coil. The primary coil is con

nected to a 120 V (rms) electric outlet and carries an rms current of 10 mA. What are the rms values of the voltage and current for the secondary?
Physics
1 answer:
PolarNik [594]3 years ago
3 0

To solve this problem we need to use the induced voltage ratio law with respect to the number of turns in a solenoid. So

\frac{\epsilon_2}{\epsilon_1} = -\frac{N_2}{N_1}

For the given values we have to

N_1 = 400

N_2 = 100

\epsilon_2 = 120V

Replacing we have that,

\frac{\epsilon_2}{120} = -\frac{100}{400}

\epsilon = 30V

Therefore the RMS value for secondary is 30V.

The current can be calculated at the same way, but here are inversely proportional then,

\frac{I_2}{I_1} = -\frac{N_1}{N_2}

Replacing we have

\frac{I_2}{10mA} = -\frac{400}{100}

I_2 = 40mA

Therefore the rms value of current for secondary is 40mA

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