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3 years ago

Question 4 (1 point)

Physics

1 answer:

Valentin [98]3 years ago

4 0

cardiovascular endurance :))

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Help i d u m b ples!!!!!!!!1111

andrew-mc [135]

Answer: b and c are the same so that leaves you with a and d I believe it's d not sure hope this helps ®:]©™

Explanation:

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3 years ago

The amount of matter I’m an object is know as

Oduvanchick [21]

The amount of matter I’m an object is know as <em>the object's mass</em> .

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4 years ago

A student finds an unlabeled bottle of liquid under

s344n2d4d5 [400]

Answer:

C. Adding some of the unknown liquid to red litmus paper.

Explanation:

Since the student doesn't know what the liquid is, it is not safe to experiment with it by boiling, cooling, or adding water to it. The safest option would be to add a small bit of the liquid to the litmus paper, which will identify the liquid as neutral, basic, or acidic.

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4 years ago

Read 2 more answers

1. Define weight

bogdanovich [222]

Answer:

weight is the product of mass andgravitational acceleration expressed in newtons.
w=mg
w=mg ....w=50kg X 9.8m/s...w=490N

4 0

3 years ago

A 120N box is being pushed across the surface that has a frictional force of 3N. If the box is being pushed with a constant forc

VashaNatasha [74]

Answer:

Net Force = 10 N

acceleration: $a=0.817 \frac{m}{s^2}$

Explanation:

1) The net force on the box is the applied force (F = 13 N) minus the friction force (f = 3 N), Therefore, net force = 10 N

See attached free body diagram.

2) To find the box's acceleration, we need first to find the mass of the box (since they are giving us its weight in Newtons). To do such we use the equation for weight and solve for the box's mass:

$weight=m*g\\120 N = m*9.8\frac{m}{s^2} \\\frac{120}{9.8} kg = m\\m=12.24 kg$

Now we can find the box's acceleration by using the equation for the net force:

$F=m*a\\10N = 12.24 kg * a\\\frac{10}{12.24} \frac{m}{s^2} =a\\a=0.817 \frac{m}{s^2}$

5 0

3 years ago