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Mandarinka [93]
3 years ago
13

What is a big five trait

Physics
1 answer:
almond37 [142]3 years ago
8 0

Answer:

Big 5 Traits are openness conscientiousness, extraversion, agreeableness, and neuroticism.

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A professional racecar driver buys a car that can accelerate at 5.9 m/s2. The racer decides to race against another driver in a
3241004551 [841]

Answer:

(a) Time will be t = 3.56 sec

(b) Distance traveled by car when they are side by side is 37.38712 m

(b) Velocity of race car = 21.004 m/sec

velocity of stock car = 12.816 m/sec            

Explanation:

We have given acceleration of the car a_1=5.9m/sec^2

Acceleration of the stock car a_2=3.6m/sec^2

When 1st car overtakes the second car then distance traveled by both the car will be same

(a) So s_1=s_2

As both car starts from rest so initial velocity of both car will be 0 m/sec

It is given that stock car leaves 1 sec before

So \frac{1}{2}\times 5.9\times t^2=\frac{1}{2}\times (t+1)^2\times 3.6

After solving t = 3.56 sec

(b) From second equation of motion s=ut+\frac{1}{2}at^2=0\times 3.56+\frac{1}{2}\times 5.9\times 3.56^2=37.38712m

(c) From first equation pf motion v = u+at

So velocity of race car v = 0+5.9×3.56 = 21.004 m/sec

Velocity of stock car v = 0+ 3.6×3.56 = 12.816 m/sec

3 0
3 years ago
Adding powdered Gatorade to water makes a tasty solution. What is the solvent in this example? A) water B) salt and sugar C) Gat
oksano4ka [1.4K]

Answer: The correct answer is A.

Explanation: In a solution, the substance which is in larger proportion is called as a solvent and the substance which is in smaller proportion is called as a solute.

When we mix a powdered Gatorade in the water, the Gatorade is present smaller proportion and hence will be considered as a solute in a solution and water is present in larger proportion and will be considered as solvent in a solution.

Hence, the correct option is A.

6 0
3 years ago
Identity the following on the wave shown below:
Marta_Voda [28]

Explanation:

Your wavelength is 0.4

Yout Amplitude is 1

7 0
2 years ago
One of the main factors driving improvements in the cost and complexity of integrated circuits (ICs) is improvements in photolit
nika2105 [10]

Answer:

0.000003782 m

0.000001891 m

0.000001197125 m

Explanation:

\lambda = Wavelength = 248 nm

D = Diameter of beam = 1 cm

f = Focal length = 0.625 cm

The angle is given by

\theta=\dfrac{1.22\lambda}{D}

The width is given by

d=2\theta f\\\Rightarrow d=2\dfrac{1.22\lambda f}{D}\\\Rightarrow d=2\dfrac{1.22\times 248\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.000003782\ m

The required width is 0.000003782 m

Minimum resolvable line separation is given by

\dfrac{0.000003782}{2}=0.000001891\ m

The minimum resolvable line separation between adjacent lines is 0.000001891 m

when \lambda=157\ nm

d=2\dfrac{1.22\times 157\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.00000239425\ m

The new minimum resolvable line separation between adjacent lines is

\dfrac{0.00000239425}{2}=0.000001197125\ m

6 0
3 years ago
Calculate 2 x 10^-3cm ÷ 2.5 x 10^4cm
Mamont248 [21]
Here is your answer:

First find the notations:

2×10^-3
=0002
And...
2.5×10^4=25000

Then divide:

0002÷25000=8E-9

Your answer:
=8 x 10-8
3 0
2 years ago
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