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satela [25.4K]
3 years ago
10

When is the color emitted from an atom

Chemistry
1 answer:
exis [7]3 years ago
5 0

Answer:

Color is emitted from an atom when an electron jumps from a higher energy level to a lower energy level

Explanation:

According to Bohr's model of the atom, electrons are arranged into circular orbits, each orbit corresponding to a precise energy level.

In this model of the atom, electrons cannot be between two orbits: this means that the energy level of the atom are discrete, so they can only assume certain values.

As a result, when an electron jumps between two energy levels, it emits/absorbs a photon whose energy is equal to the difference in energy between the two levels.

In particular:

- If an electron jumps from a lower energy level to a higher energy level, it absorbs a photon

- If an electron jumps from a higher energy level to a lower energy level, it emits a photon

The energy of the emitted photon is equal to the difference in energy between the two levels, and it is related to the wavelength \lambda of the photon by

E=\frac{hc}{\lambda}

where h is the Planck's constant and c the speed of light.

For usual gases, the value of the energy E is such that the value of the wavelength \lambda falls within the visible light range of the electronmagnetic spectrums, so we observe light emitted as different colors, depending on the wavelength.

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Andru [333]

Answer:

245.66g of NH₄Cl is the mass we need to add to obtain the desire pH

Explanation:

The mixture of NH3/NH4Cl produce a buffer. We can find the pH of a buffer using H-H equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] is the molar concentration of the base, NH₃, and [HA] molar concentration of the acid, NH₄⁺. This molar concentration can be taken as the moles of each chemical</em>

<em />

First, we need to find pKa of NH₃ using Kb. Then, the moles of NH₃ and finally replace these values in H-H equation to solve moles of NH₄Cl we need to obtain the desire pH.

  • <em>pKa NH₃/NH₄⁺</em>

pKb = - log Kb

pKb = -log 1.8x10⁻⁵ = <em>4.74</em>

pKa = 14 - pKb

pKa = 14 - 4.74

pKa = 9.26

  • <em>Moles NH₃</em>

<em>2.00L ₓ (0.200mol NH₃ / L) = 0.400 moles NH₃</em>

  • <em>H-H equation:</em>

pH = pKa + log [NH₃] / [NH₄Cl]

8.20 = 9.26 + log [0.400 moles] / [NH₄Cl]

-1.06 =  log [0.400 moles] / [NH₄Cl]

0.0087 =  [0.400 moles] / [NH₄Cl]

[NH₄Cl] = 0.400 moles / 0.0087

[NH₄Cl] = 4.59 moles of NH₄Cl we need to add to original solution to obtain a pH of 8.20. In grams (Using molar mass NH₄Cl=53.491g/mol):

4.59 moles NH₄Cl ₓ (53.491g / mol) =

<h3>245.66g of NH₄Cl is the mass we need to add to obtain the desire pH</h3>

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3 0
4 years ago
The incredible catalytic power of enzymes can perhaps best be appreciated by imagining how challenging life would be without jus
ioda

Answer:

t = 7.58 * 10¹⁹ seconds

Explanation:

First order rate constant is given as,

k =  (2.303 /t) log  [A₀] /[Aₙ]

where  [A₀]  is the initial concentraion of the reactant; [Aₙ] is the concentration of the reactant at time, <em>t</em>

[A₀]  = 615 calories;

[Aₙ] = 615 - 480 = 135 calories

k = 2.00 * 10⁻²⁰ sec⁻¹

substituting the values in the equation of the rate constant;

2.00 * 10⁻²⁰ sec⁻¹ = (2.303/t) log (615/135)

(2.00 * 10⁻²⁰ sec⁻¹) / log (615/135) = (2.303/t)

t = 2.303 / 3.037 * 10⁻²⁰

t = 7.58 * 10¹⁹ seconds

8 0
3 years ago
Which postmortem parameter reaches a maximum at 12 hours and is gone within 36 to 48 hours?1.rigor mortis2.cloudiness of the eye
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IMixing combined with skip voting
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Anuta_ua [19.1K]
A0 = 1
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This can be solved by guessing and checking and making sure that all atoms on the left side are accounted for on the right side. Both sides must have the same amount of atoms or the balancing is not correct.
7 0
3 years ago
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