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3 years ago

Fill in the coefficients that will balance the following reaction a0h2so4 + a1koh → a2k2so4 + a3hoh

2 answers:

7 0

A0 = 1
a1 = 2
a2 = 1
a3 = 2

This can be solved by guessing and checking and making sure that all atoms on the left side are accounted for on the right side. Both sides must have the same amount of atoms or the balancing is not correct.

iris [78.8K]3 years ago

6 0

a0h2so4 + a1koh → a2k2so4 + a3hoh

The balanced chemical reaction is:

H2SO4 + 2KOH → K2SO4 + 2H2O

hence,

a0 = 1

a1 = 2

a2 = 1

a3 = 2

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Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded co

shusha [124]

This question is an incomplete question, here is a complete question.

Perform the following calculation. Report the answer using the proper number of significant figures.

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}=?$

Answer : The answer will be, $3.46J/g.K$

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

The given expression is,

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}$

$\frac{1.012\times 10^{-3}J}{(0.025456g)\times (0.0115)K}$

$\Rightarrow 3.4569J/g.K$

In the given expression, 1.012 has 4 significant figures, 0.025456 has 5 significant figures and 0.0115 has 3 significant figures. From this we conclude that 3 is the least significant figures in this problem. So, the answer should be in 3 significant figures.

Thus, the answer will be $3.46J/g.K$

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Answer: Option (d) is the correct answer.

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