Question

How many moles are in 68.5 liters of oxygen gas at STP?

Answer 1

Answer:

3.0580 moles are in 68.5 liters of oxygen gas at STP

Explanation:

Let the number of moles of oxygen gas be n

Volume occupied by n moles of oxygen gas  at STP = 68.5 L

At STP, 1 mol of gas occupies 22.4 L

Then 68.4 L of volume will be occupied by:

$\frac{1}{22.4} \times 68.5 L=3.0580 mol$

3.0580 moles are in 68.5 liters of oxygen gas at STP

Answer 2

Since we know that one mole of any gas at STP is equal to 22.4 L we can multiply 135L by the following conversion: 1 mole/22.4L. When you set up the problem it looks like this…: (135L)x 1 mole/22.4L =6.03 moles of oxygen gas The liters cancel out and you are left with moles as your units.


So your answer is then 3.058