The total hours that are necessary to reduce carbon dioxide level to at least 325 ppm are 4 hours.
<h3>How does carbon dioxide concentration change over time?</h3>
First hour:
- 1,100 - 20 %
- 1,100 - 220 = 880
Second hour:
- 704 - 20%
- 704 - 140.8 =663.2
- 663.2 - 20%
- 663.2 - 132.64 = 530.56
Third hour:
- 530.56 - 20%
- 530.56 - 106.112 = 424.44
- 424.44 - 20%
- 424.44 - 84.88 = 339.55
Fourth hour:
- 339.55 - 20%
- 339.55 - 67.91 = 271.64
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Answer:
155fts
Explanation:
We apply the bernoulli's equation to get the depth of water.
We have the following information
P1 = pressure at top water surface = 0
V1 = velocity at too water surface = 0
X1 = height of water surface = h
Hf = friction loss = 0
P2 = pressure at exit = 0
V2 = velocity at exit if penstock = 100ft/s
X2 = height of penstock = 0
g = acceleration due to gravity = 32.2ft/s²
Applying these values to the equation
0 + 0 + h = 0 + v2²/2g +0 + 0
= h = 100²/2x32.2
= 10000/64.4
= 155.28ft
= 155
Answer:
Anne is an aeronautical engineer.
Explanation:
Answer:
// This function is written in C++ Programming Language
// Comments are used for explanatory purpose
// The scope of this code segment is limited to only the required function/module
// Program starts here
#include<iostream>
using namespace std;
int main ()
{
// Main method is omitted
}
// Declare function
void proverb(int digit)
{
if(digit == 1) // check if digit is 1
{
cout << "Now is the time for all good men to come to the aid of their party.";
}
else //Otherwise
{
cout << "Now is the time for all good men to come to the aid of their country";
}
}
// End of program
Answer:
>>pounds=13.2
>>kilos=pounds/2.2
Explanation:
Using Matlab to write the program, consider at any time when the weight in pounds is 13.2 lb, this variable of weight is created in MATLAB by typing >>pounds=13.2. To convert it from lb to Kg, we simply divide it by 2.2 hence the second command to created is kilos. For this, the output of the program will be 6 Kg.
