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Veronika [31]
3 years ago
7

When you sneeze, the air in your lungs accelerates from rest to 155 km/h in approximately 0.70 s . what is the acceleration of t

he air in m/s2?
Physics
1 answer:
ollegr [7]3 years ago
6 0
<span>62 m/s^2 First, convert 155 km/h to m/s 155 km/h * 1000 m/km / 60 min/h / 60 s/h = 43.05556 m/s Now take the speed in m/s and divide by the number of seconds it took to accelerate it to that speed. 43.05556 m/s / 0.70 s = 61.5 m/s^2 Since we only have 2 significant figures, round the result to 2 figures. 61.5 m/s^2 = 62 m/s^2</span>
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The car travels 25 miles in the first 0.5 hours
Westkost [7]

Answer:

\huge\boxed{\sf v = 50\ miles / hr}

Explanation:

<u>Given Data:</u>

Distance = S = 25 miles

Time = t = 0.5 hours

<u>Required:</u>

Speed = v = ?

<u>Formula:</u>

v = S/t

<u>Solution:</u>

v = 25 / 0.5

v = 50 miles / hr

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
4 0
3 years ago
an object is held 33.5 cm from a convex mirror. it creates a virtual image of magnification 0.253. what is the focal length of t
MaRussiya [10]

Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

7 0
2 years ago
a load of 400 Newton is lifted by a first class lever in which the load is at the distance of 20 cm and the effort is at the dis
Len [333]

Answer:

  1. solution,
  2. Given
  3. load =400N
  4. ld=0.2m
  5. ed=0.6m
  6. effort =150N

Explanation:

efficiency =output work/input work ×100%

l×ld/e×ed×100%

400×0.2/150×0.6×100%

80/90×100%

88.89%ans

7 0
3 years ago
A certain white dwarf star was once an average star like our Sun. But now it is in the last stage of its evolution and is the si
solmaris [256]

Answer:

4.384 * 10^13

Explanation:

Given the expression :

[(6.67 * 10^-11) * (1.99 * 10^30)] ÷ [(1.74*10^3)*(1.74*10^3)]

Applying the laws of indices

[(6.67 * 1.99) *10^(-11 + 30)] ÷ [(1.74 * 1.74) * 10^3+3]

13.2733 * 10^19 ÷ 3.0276 * 10^6

(13.2733 / 3.0276) * 10^(19 - 6)

4.3840996 * 10^13

= 4.384 * 10^13

6 0
3 years ago
As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o
STatiana [176]

Answer:

3335400 N/m² or 483.75889 lb/in²

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

A = Area = 1.5 cm²

m = Mass of woman = 51 kg

F = Force = mg

When we divide force by area we get pressure

P=\frac{F}{A}\\\Rightarrow P=\frac{mg}{A}\\\Rightarrow P=\frac{51\times 9.81}{1.5\times 10^{-4}}\\\Rightarrow P=3335400\ N/m^2

1\ N/m^2=\frac{1}{6894.757}\ lb/in^2

3335400\ N/m^2=3335400\times \frac{1}{6894.757}\ lb/in^2=483.75889\ lb/in^2

The pressure exerted on the floor is 3335400 N/m² or 483.75889 lb/in²

7 0
3 years ago
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