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pogonyaev
3 years ago
5

Which sequence shows all the colors of visible light arranged from shortest to longest wavelength?

Physics
2 answers:
sertanlavr [38]3 years ago
6 1

Answer: The correct answer is VIBGYOR.

Visible light is the part of the electromagnetic spectrum that is detected by human eyes. We can see the different colors in the spectrum of visible light because of the wavelength that corresponds to a particular light and is reflected back to our eyes.

The visible light spectrum ranges from Voilet ( 400 nm) to red (700nm).

Thus, the sequence showing the colors of visible light from shortest to longest wavelength is- V- Voilet, I- Indigo, B- Blue, G- green, Y- yellow, O- orange, R- red

Cloud [144]3 years ago
4 1
Violet
indigo
blue
green
yellow 
orange
red
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Estimate the volume of a piece of molecular cloud that has the same amount of water as your body.
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Question:

The water molecules now in your body were once part of a molecular cloud. Only about onemillionth of the mass of a molecular cloud is in the form of water molecules, and the mass density of such a cloud is roughly 2.0×10−21 g/cm^3.

Estimate the volume of a piece of molecular cloud that has the same amount of water as your body.

Answer:

The volume of cloud that has the same density as the amount of water in our body is 1.4×10²⁵ cm³

Explanation:

Here, we have mass density of cloud  =  2.0×10⁻²¹ g/cm^3

Density = Mass/Volume

Volume = Mass/Density =   If the mass is 40 kg and the body is made up of 70% by mass of water, we have

28 kg water = 28000 g

Therefore the Volume = 28 kg/ 2.0×10⁻²¹ g/cm^3 = 1.4×10¹⁹ m³ = 1.4×10²⁵ cm³.

Therefore, the volume of cloud that has the same density as the amount of water in our body = 1.4×10²⁵ cm³.

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3 years ago
If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v​
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Answer:

v = 6i + 12j + 4k

Explanation:

Find the magnitude of the direction vector.

√(3² + 6² + 2²) = 7

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Multiply by the magnitude of v.

v = 14 (3/7 i + 6/7 j + 2/7 k)

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A diffraction pattern forms when light passes through a single slit. The wavelength of the light is 691 nm. Determine the angle
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Explanation:

Given that,

Wavelength of the light, \lambda=691\ nm=691\times 10^{-9}\ m

(a) Slit width, a=3.8\times 10^{-4}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-4}}

\theta=0.104^{\circ}

(b) Slit width, a=3.8\times 10^{-6}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-6}}

\theta=10.47^{\circ}

Hence, this is the required solution.

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