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3 years ago

Need help please on this EDPUZZLE

Chemistry

1 answer:

yan [13]3 years ago

3 0

Answer:

they change the state of matter

Explanation:

Physical properties can be observed or measured without changing the composition of matter

Chemical properties are only observed during a chemical reaction and thus changing the substance's chemical composition

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How many oxygen atoms are present in 30g of glucose?

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3 years ago

How many joules of heat are required to raise the temperature of 320.0 grams of water from 24.2°C to 50.8°C? Heat capacity of wa

balu736 [363]

Answer:

35750.4 Joules

Explanation:

Using the formula as follows;

Q = m × c × ∆T

Where;

Q = amount of heat (joules)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to the provided information,

mass (m) = 320.0 grams

c = 4.2 J/g°C

∆T = (50.8°C - 24.2°C) = 26.6°C

Q = ?

Using; Q = m × c × ∆T

Q = 320 × 4.2 × 26.6

Q = 35750.4 J

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3 years ago

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici

Brut [27]

Question:

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

Answer:

The mean activity coefficient for HCl solution is 0.78.

Explanation:

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

$E=E_{0}-0.0514 \mathrm{V} \ln \gamma$

As we know that $E_{0}$ = 0.22 V and E = 0.342 V, the equation will become

$0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma$

$0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)$

$0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)$

$\frac{0.12}{0.0514}=-\ln (0.124 \gamma)$

$-2.3346=\ln (0.124 \gamma)$

$e^{-2.3346}=0.124 \gamma$

$0.0968=0.124 \gamma$

$\gamma=\frac{0.0968}{0.124}=0.78$

So, the mean activity coefficient is 0.78.

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3 years ago

How do scientists classify intrusive igneous features? according to shape, texture, and their distance from the nearest volcanic

Nataliya [291]

according to shape, size, and their relationship to surrounding layers of rock

Explanation:

Scientists classify intrusive features according to their shape, size and relationship to surrounding layers of rocks.

Intrusive igneous features are the sills, di/kes, batholith, laccoiith, lopolith e.t.c

When magma cools and solidifies within the earth crust, they form intrusive igneous rocks.
Intrusive igneous rocks differs from one another in their shape, size and relationship to surrounding rocks.
For example, batholith is a large intrusive body that extends for several kilometers in the earth surface.
Sills and di/kes are smaller bodies. Sills forms parallel to orientation of rocks in an area. Di/kes are known to cut across the orientation.

Learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

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3 years ago

1. How do organisms maintain homeostasis?

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Answer:

Maintenance of homeostasis usually involves negative feedback loops. These loops act to oppose the stimulus, or cue, that triggers them.

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