The very top layer on earth gets the most leathering because the rain, sleet, snow, ect. Mostly hits that top surface...
The other layers in earth dont get that much weathering because, well.... Like i said, everything mainly happens on the top layer.
~Hope this helped, anymore questions please ask! :)
This is a good riddle. The answer is ICE, because ice can break things, even ships like the titanic and it also makes steel weak but when the sun comes it melts away so it’s cowers away.
<span>D. Bodies directly surrounding the body</span>
Answer:
Adaptations
Explanation:
Adaptation is simply defined as a specific characteristics of an animal or plant which can be a body part, body covering, or behavior that helps an animal or plant survive in its environment.
The common types of Adaptations includes Physical adaptation which entails a change to a part of the body and Behavioral adaptation which is simply what an animal does in response to an external stimulus.
Examples of Adaptation includes Hibernation, Camouflage, Mimicry, Whiskers, Beaks and others. In plants, seed colour, hard endocarp, secretions e. t. c helps them survive in their environment.
The molar mass of a, b and c at STP is calculated as below
At STP T is always= 273 Kelvin and ,P= 1.0 atm
by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation
that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula
that is molar mass = (mass x RT)/ PV
density is always = mass/volume
therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K
the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol
the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol
the molar mass of c
=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol
therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol