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Juli2301 [7.4K]
3 years ago
11

Phosphoric acid h3po4 is an important industrial chemical used in fertilizers, detergents, and the food industry. it is produced

by two different methods. In the electric furnace method elemental phosphorus P4 is in air to form P4O10, which is then combined with water to give H3PO4. In the wet process the mineral phosphate rock Ca5(PO4)3F is combined with sulfuric acid to give H3PO4 and HF and CaSO4.
Write equations for these processes, and classify each step as preciptation, acid-base, or redox reaction
Chemistry
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

1)   P₄ + 5O₂ → P₄O₁₀  redox reaction

2)   P₄O₁₀ + 6H₂O → 4H₃PO₄  acid-base reaction

3)   Ca₅(PO₄)₃F + 5H₂SO₄ → 3H₃PO₄ + HF + 5CaSO₄  precipitation reaction

Explanation:

The reactions that take place in the <u>electric furnace method</u> are:

1)   P₄ + 5O₂ → P₄O₁₀

This is a redox reaction, because the oxidation state of the reactants is changed.

2)   P₄O₁₀ + 6H₂O → 4H₃PO₄

This is an acid-base reaction, because there's an exchange of H⁺ species.

The reaction that takes place in the <u>wet process</u> is:

3)   Ca₅(PO₄)₃F + 5H₂SO₄ → 3H₃PO₄ + HF + 5CaSO₄

This is an precipitation reaction, because a precipitate (a solid phase in a liquid phase) is formed.

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A piston containing 0.120moles of methane gas, CH4, has a volume of 2.12liters. If methane is added until the volume is increase
earnstyle [38]

Answer:

2.83 g

Explanation:

At constant temperature and pressure, Using Avogadro's law

\frac {V_1}{n_1}=\frac {V_2}{n_2}

Given ,  

V₁ = 2.12 L

V₂ = 3.12 L

n₁ = 0.120 moles

n₂ = ?

Using above equation as:

\frac{2.12}{0.120}=\frac{3.12}{n_2}

2.12n_2=0.12\cdot \:3.12

2.12n_2=0.3744

n_2=\frac{0.3744}{2.12}

n_2=0.17660

n₂ = 0.17660 moles

Molar mass of methane gas = 16.05 g/mol

So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g

<u>2.83 g  are in the piston.</u>

8 0
4 years ago
Hi can someone please help me find the average for these temperatures? I need them asap
goblinko [34]

Answer:

55 degrees F - cold water

120 degrees F

the last on I don't know

5 0
2 years ago
A rigid container of O has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?
tia_tia [17]

Answer:

P₂ = 130.18 kPa

Explanation:

In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:

P₁/T₁ = P₂/T₂   (1)

From here, we can solve for the Pressure at 273 K:

P₂ = P₁ * T₂ / T₁   (2)

Now, all we need to do is replace the given data and solve for P₂:

P₂ = 340 * 273 / 713

<h2>P₂ = 130.18 kPa</h2>

Hope this helps

4 0
3 years ago
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Keith_Richards [23]

T=41+273=314 k

M=(12)+(16×2)=44g/mol

d=PM/RT

d=685×44/0.0821×314

d=1169.15 g/L

5 0
3 years ago
Groundwater in an area flows at a speed of 4km/h. How long would it take the water to flow 10 km t it’s springs
joja [24]
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