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Juli2301 [7.4K]
2 years ago
11

Phosphoric acid h3po4 is an important industrial chemical used in fertilizers, detergents, and the food industry. it is produced

by two different methods. In the electric furnace method elemental phosphorus P4 is in air to form P4O10, which is then combined with water to give H3PO4. In the wet process the mineral phosphate rock Ca5(PO4)3F is combined with sulfuric acid to give H3PO4 and HF and CaSO4.
Write equations for these processes, and classify each step as preciptation, acid-base, or redox reaction
Chemistry
1 answer:
kenny6666 [7]2 years ago
7 0

Answer:

1)   P₄ + 5O₂ → P₄O₁₀  redox reaction

2)   P₄O₁₀ + 6H₂O → 4H₃PO₄  acid-base reaction

3)   Ca₅(PO₄)₃F + 5H₂SO₄ → 3H₃PO₄ + HF + 5CaSO₄  precipitation reaction

Explanation:

The reactions that take place in the <u>electric furnace method</u> are:

1)   P₄ + 5O₂ → P₄O₁₀

This is a redox reaction, because the oxidation state of the reactants is changed.

2)   P₄O₁₀ + 6H₂O → 4H₃PO₄

This is an acid-base reaction, because there's an exchange of H⁺ species.

The reaction that takes place in the <u>wet process</u> is:

3)   Ca₅(PO₄)₃F + 5H₂SO₄ → 3H₃PO₄ + HF + 5CaSO₄

This is an precipitation reaction, because a precipitate (a solid phase in a liquid phase) is formed.

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How to find the final temperature
sveta [45]

Answer:

The final temperature will be "12.37°".

Explanation:

The given values are:

mass,

m = 0.125 kg

Initial temperature,

c = 22.0°C

Time,

Δt = 4.5 min

As we know,

⇒  q=mc \Delta t

On putting the estimated values, we get

⇒     =0.125\times 22.0\times 4.5

⇒     =12.37^{\circ}

8 0
2 years ago
Calculate the morality of a 35.4% (by mass) aqueous solution of phosphoric acid (H3PO4). Molar mass of H3PO4 is 98.00g/mol
Butoxors [25]

Answer:

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3 0
2 years ago
Why the partial charge on H in HF is more positive than the partial charge on H in HBr
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8 0
3 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
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