Question

Part of one row of the periodic table is shown. 4 blue boxes in a row. The first has S n at the center and 50 above with tin and 118.71 below. The second has S b at the center and 51 above with antimony and 121.76 below. The third has T e at the center and 52 above with tellurium and 127.60 below. The fourth has I at the center and 53 above with iodine and 126.90 below. Which element’s atoms have the greatest average number of neutrons? tin (Sn) antimony (Sb) tellurium (Te) iodine (I)

Answer 1

Answer:

Atoms of tellurium (Te) have the greatest average number of neutrons equal to 76.

Explanation:

In the periodic table, Elements are represented with their respected symbols. Above the symbol is the elements atomic number which is equal to the number of protons in each atom. Below the symbol is the mass number of that element which is roughly equal to the sum of neutrons and protons of that atom.

To calculate the number of neutrons we can take the difference of Atomic number and mass number:

Number of neutrons = mass number - atomic number

- Tin:

Atomic number = 50

Mass number = 119

Number of neutrons = mass number - atomic number = 119 - 50

Number of neutrons = 69

- Antimony(Sb):

Atomic number = 51

Mass number = 122

Number of neutrons = mass number - atomic number = 122 - 51

Number of neutrons = 71

- Tellurium(Te):

Atomic number = 52

Mass number = 128

Number of neutrons = mass number - atomic number = 128 - 52

Number of neutrons = 76

- Iodine(I):

Atomic number = 53

Mass number = 127

Number of neutrons = mass number - atomic number = 127 - 53

Number of neutrons = 74

Here, the greatest number of neutrons is for the atoms of Tellurium(Te).

Answer 2

Answer:

if you dont like to read its

Explanation:

tellurium (Te)