1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pashok25 [27]
3 years ago
12

What is the formula for average velocity?

Physics
1 answer:
MissTica3 years ago
5 0

Velocity = distance/time

You might be interested in
In the Sun, fusion reactions create helium nuclei. To form each helium
seraphim [82]
D is the answer. Bc the pointy
6 0
3 years ago
Read 2 more answers
How many types of quarks are there?<br> a. 2<br> b. 4<br> c. 6<br> d. 8
Nostrana [21]
There are 6 types of quarks.

Answer: C. 6
8 0
3 years ago
Read 2 more answers
Explain why a schoolbus appears to be yellow.
Dennis_Churaev [7]
I think the answer is B.
4 0
3 years ago
How do you do this? Plz help answer
Contact [7]

Answer: Really

Explanation:

Just look it up for this page and maybe you will find an anwser sheet.

7 0
3 years ago
Suppose that Hubble's constant were H0 = 51 km/s/Mly (which is not its actual value). What would the approximate age of the univ
bija089 [108]

Given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Given the data in the question;

Hubble's constant; H_0 = 51km/s/Mly

Age of the universe; t = \ ?

We know that, the reciprocal of the Hubble's constant ( H_0 ) gives an estimate of the age of the universe ( t ). It is expressed as:

Age\ of\ Universe; t = \frac{1}{H_0}

Now,

Hubble's constant; H_0 = 51km/s/Mly

We know that;

1\ light\ years = 9.46*10^{15}m

so

1\ Million\ light\ years = [9.46 * 10^{15}m] * 10^6 = 9.46 * 10^{21}m

Therefore;

H_0 = 51\frac{km}{\frac{s}{Mly} } = 51000\frac{m}{s\ *\ Mly}  \\\\H_0 = 51000\frac{m}{s\ *\ (9.46*10^{21}m)} \\\\H_0 =  5.39 *10^{-18}s^{-1}\\

Now, we input this Hubble's constant value into our equation;

Age\ of\ Universe; t = \frac{1}{H_0}\\\\t = \frac{1}{ 5.39 *10^{-18}s^{-1}} \\\\t = 1.855 * 10^{17}s\\\\We\ convert\ to\ years\\\\t =  \frac{ 1.855 * 10^{17}}{60*60*24*365}yrs \\\\t = \frac{ 1.855 * 10^{17}}{31536000}yrs\\\\t = 5.88 *10^9 years

Therefore, given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Learn more: brainly.com/question/14019680

6 0
3 years ago
Other questions:
  • A wheel of radius 14 inches is rotating 0.5 rad/s. what is the linear speed v, the angular speed in rpm, and the angular speed i
    13·1 answer
  • The Tesla Roadster electric car is rated at 16.8kW how much energy does it use during a one hour car drive
    7·1 answer
  • Vector A is 3 m long and vector B is 4 m long. The length
    13·1 answer
  • Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What
    5·1 answer
  • Small, icy bodies that have highly eccentric orbits and can be found in the Oort cloud or the Kuiper belt are called ____.
    15·1 answer
  • Please help me with this question
    7·1 answer
  • Approximately what percentage of Earth’s radius is represented by the crust?
    7·1 answer
  • Can yall please help!!
    5·1 answer
  • A spherical, non-conducting shell of inner radius = 10 cm and outer radius = 15 cm carries a total charge Q = 13 μC distributed
    15·1 answer
  • An unladen swallow that weighs 0.03 kg flies straight northeast a distance of 125 km in 4.0 hours. With the x x direction due ea
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!