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RSB [31]
3 years ago
11

Your shopping cart has mass of 65 kg. In order of accelerate the shopping cart down an aisle at 0.3 m/sec^2, what force would yo

u need to use or apply to the cart?
Physics
1 answer:
aleksklad [387]3 years ago
4 0
Fnet = m x a
= 65kg x 0.3m/s^2
= 19.5N
This is assuming that there is no friction or other external forces!
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A tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560
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The answer is 78.1 I already checked it
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Look at paths of the projectiles. What effect does air resistance have on the projectile?
inna [77]

Answer:

Therefore the resistance of the air makes the movement not parabolic but shorter in each direction

Explanation:

The projectile motion is described by the kinematics equations giving a parabolic trajectory, where on the x axis there is no acceleration and on the y axis the acceleration is the acceleration of gravity.

When the air resistance is taken into account it can be approximated as a force that opposes the movement that for low speeds is proportional to the speed of the space.

Consequently, the movement in the axis and the acceleration is less, in some cases it can be so small that the constant handle speed, in this case, is called terminal velocity.

On the x-axis the friction force creates an acceleration in the negative direction of the movement that the projectile has to brake.

Therefore the resistance of the air makes the movement not parabolic but shorter in each direction.

6 0
3 years ago
Would you buy a pair of shoes from the same company that sold Jack his shoes? Why or why not?
LenKa [72]

Answer:

Maybe

Explanation:

It depends. If he says the shoes sucked than no because they suck-

But if he really liked the shoes and said it was really good than yes

I would buy the shoes

8 0
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An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F
ololo11 [35]

Answer

given,

mass of jogger  = 67 kg

speed in east direction = 2.3 m/s

mass of jogger 2 = 70 Kg

speed  = 1.3 m/s  in  61 ° north of east.

jogger one

P_1 = m_1 v_1 \hat{i}

P_1 = 67 \times 2.3\hat{i}

P_1 = 154.1 \hat{i}

P_2 = m_2 v_2 \hat{i} +m_2 v_2 \hat{j}

P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}

P_2 = 70\times 1.3 cos 61^0 \hat{i} +70\times 1.3 sin 61^0\hat{j}

P_2 = 44.12\hat{i} +79.59\hat{j}

now

P = P₁ + P₂

P = 198.22 \hat{i} +79.59 \hat{j}

magnitude

P = \sqrt{198.22^2 + 79.59^2}

P =213.60 kg.m/s

\theta = tan^{-1}\dfrac{79.59}{198.22}

\theta = 21.87

the angle is \theta = 21.87 north of east

7 0
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How does a bicycles kinetic energy change when it slows down?
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The kinetic energy decreases 
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