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sergeinik [125]
3 years ago
12

When you hold your hands at your sides, you may have noticed that the veins sometimes bulge--the height difference between your

heart and your hands produces increased pressure in the veins. The same thing happens in the arteries. If the average arterial pressure at your heart is a typical 100 mmHg, what is the average arterial pressure in your hands when they are held at your side? Assume your hands are 60 cm below your heart.
Physics
1 answer:
hodyreva [135]3 years ago
7 0

To solve this problem it is necessary to use the concepts related to pressure and pressure, absolute and atmospheric.

Average arterial pressure in the hands,

P = 100mmHg+ h*\rho_{blood}g

Where,

P = Pressure

h = height (at this case the length of the arm)

Replacing with our values

P = 100mm(Hg)+(600mm)(\frac{\rho_{blood}}{\rho_{mercury}})(Hg)

P = 100mmHg+600*\frac{1060}{13600}mmHg

P = 100mmHg+46.765mmHg

P = 146.765mmHg

Where,

\rho_{blood} = 1060Kg/m^3

\rho_{mercury}=13600Kg/m^3

Therefore the pressure is 146.765mmHg

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The height of the building using second equation of motion is 35.721 m

What is the second equation of motion?

In kinematics, equations of motion are referred to as the fundamental principles of an object's motion, including velocity, location, and acceleration that occur at variable time intervals. These three motion equations control motion in all three dimensions of an item.

Second equation of motion: s = ut +  a(t^2)/2

where,

s = displacement

u = initial velocity

v = final velocity

a = acceleration

t = time of motion

Given, a = 9.8 m/s/s

           t = 2.7 s

Using this equation we find the height of the building,

s = ut +  a(t^2)/2

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  = 71.442/2

  = 35.721 m

Hence, the height of the building is 35.721 m

To learn more about equations of motions from the given link

brainly.com/question/25951773

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1 year ago
According to the text, the specific things that people want in life are called:​
timofeeve [1]

Answer: wants

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People want it but don’t need it

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3 years ago
A tire placed on a balancing machine in a service station starts from rest and turns through 4.0 rev in 1.0 s before reaching it
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Answer:

a  = 50.26 rad/s^2

Explanation:

We know that:

θ = \frac{1}{2}at^2

where θ is the angle, a the angular aceleration and t the time.

First, we need to find how many rad are equivalent to 4 rev, as:

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Finally, replacing θ by 25.13 rad and t by 1 second, we get:

25.13 rad = \frac{1}{2}a(1s)^2

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3 years ago
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A 0.208 kg particle with an initial velocity of 1.26 m/s is accelerated by a constant force of 0.766 N over a distance of 0.195
eduard

Answer:

Explanation:

Initial kinetic energy of particle

= 1/2 m V²

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This energy will be added up .

Total final kinetic energy

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=  .314 J .

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