Ask question

Ask question

All categories

3 years ago

5

Why does the unit of time enter twice in the unit of acceleration?

1 answer:

Aleks04 [339]3 years ago

8 0

Acceleration is the measurement that describes the rate of the changing the speed of the object. Mathematically, that is a = s / t
where a is acceleration, s is speed and t is time. Further, speed is the rate of changing the distance, s = d / t
With this, the unit of time is entered twice in the equation.

You might be interested in

uniform ladder of length 6.0 m and weight 300 N leans against a frictionless vertical wall. The foot of the ladder isplaced 3.0

olganol [36]

Answer:

Fx1 (6 m) sin 60 = 300 (3 m) cos 60 balancing torques about floor

Fx1 = 900 * 1/2 / 5.20 = 86.6 N this is the horizontal force that must be supplied by the wall to balance torques about the floor

This is also equal to the static force of friction that must be applied at the point of contact with the floor to balance forces in the x-direction.

Fx1 = Fx2 = 86.6 N

3 0

3 years ago

In which of these situations is convection most likely the main form of heat transfer? A.Warm air from a heater on the first flo

Kitty [74]

The answer is D.An ice cube melts when a person holds it in his hand
The heat from your body is causing the ice cube to melt

3 0

3 years ago

Read 2 more answers

When light in vacuum is incident at the polarizing angle (Brewster's angle) on a certain glass slab, the angle of refraction is

marysya [2.9K]

Answer:

Explanation:

θ( p ) + θ( r ) = 90

θ (r) = angle of refraction and θ ( p ) is polarising angle.

given θ ( r ) = 31.8

θ ( p ) = 90 - 31.8 = 58.2 degree

ii ) Tanθ ( p ) = n ( refractive index ) = Tan 58.2 = 1.6

3 0

3 years ago

The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh

Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

$v^2=v^2_o-2ax$

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

$\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}$

Next, consider that the formula for the force is:

$F=ma$

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

$F=(820kg)(0.66\frac{m}{s^2})=542.20N$

Hence, the required force to stop the car is 542.20N

4 0

1 year ago

PLEASE HELP<br> 8th grade honors science

lora16 [44]

Both of them are magnets coiled by wires.

1. The wire coiled in the first diagram, the wire is having current, Making the magnetic feild of the magnet more........

2. The wire coiling the magnet is here not having electric current making the magnetic feild smaller

7 0

3 years ago

Read 2 more answers