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Genrish500 [490]
3 years ago
9

A model hydroelectric power station produces just enough electric power to light a 6.0 W lamp. The model is found to be 80% effi

cient at converting the potential energy store of the water into electrical work. What is the input power of the water running through the pipes?
Physics
1 answer:
Savatey [412]3 years ago
4 0

You said that the useful output power from the model is 6 watts.  You also said that the model is 80% efficient.  We have no reason to doubt your word, so we know that

(useful output) / (input power) = 80% or 0.8

(6 watts) / (input power) = 0.8

Multiply each side by (input power): 6 watts = (0.8) (input power)

Divide each side by 0.8 :  Input power = (6 watts/ 0.8)

<em>Input power =  7.5 watts</em>

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The ratio is   \frac{T_1}{T_2}  = 3.965

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