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dezoksy [38]
2 years ago
8

which pole of a compass needle points north ? please give simple answer with little explaining if any :)

Physics
1 answer:
Mumz [18]2 years ago
6 0
I think the North Pole
If I understand this correctly
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Question in picture, just want to confirm answer.<br> Is the answer B?
guapka [62]

Answer:

Explanation:

yep the answer is B

6 0
2 years ago
A disk rotates at constant angular acceleration, from angular position θ1 = 16.0 rad to angular position θ2 = 76.0 rad in 5.30 s
Oliga [24]

Answer:

(a) the angular velocity at θ1 is 11.64 rad/s

(b) the angular acceleration is 0.12 rad/s^{2}

(c) the angular position was the disk initially at rest is - 428.27 rad

Explanation:

Given information :

θ1 = 16 rad

θ2 = 76 rad

ω2 = 11 rad/s

t = 5.3 s

(a) The angular velocity at θ1

First, we use the angular motion equation for constant acceleration

Δθ = (ω1+ω2)t/2

θ2 - θ1 = (ω1+ω2)t/2

ω1 + ω2 = 2 (θ2 - θ1) / t

ω1 = (2 (θ2 - θ1) / t ) - ω2

     = (2 (76-16) / 5.3) - 11

     = 11.64 rad/s

(b) the angular acceleration

ω2 = ω1 + α t

α t = ω2 - ω1

α = (ω2 - ω1)/t

  = (11.64 - 11) / 5.3

  = 0.12 rad/s^{2}

(c) the angular position was the disk initially at rest, θ0

at rest ω0 = 0

ω2^2 = ω01  t + 2 α Δθ

2 α Δθ = ω2^2

θ2 - θ0 = ω2^2  /  2 α

θ0 = θ2 -  (ω2^2) / 2 α

  = 76 - (11^{2}/ 2 x 0.12

  = 76 - 504.16

  = - 428.27 rad

4 0
3 years ago
What does force change?
Nonamiya [84]
A force is a push or pull to an object
4 0
3 years ago
Mixed powders may be categorized as​
Nastasia [14]

Answer:

<u><em>on  flow properties and free-flowing and cohesive. </em></u>

Explanation:

the power Free flowing powders do not cling together, as cohesive powders stick to each other and form that do not disperse well during mixing

6 0
3 years ago
A 7.3 cm diameter loop of wire is initially oriented so that its plane is perpendicular to a magnetic field of 0.61 T pointing u
kenny6666 [7]

Answer:

induced emf =  28.65 mV

Explanation:

given data

diameter = 7.3 cm

magnetic field = 0.61

time period = 0.13 s

to find out

magnitude of the induced emf

solution

we know radius is diameter / 2

radius = 7.3 / 2

radius = 3.65 m

so induced emf is dπ/dt  = Adb/dt

induced emf =  A × ΔB / Δt

induced emf =  πr² × ΔB / Δt

induced emf =  π (0..65)² × ( 0.61 - (-0.28))  / 0.13

induced emf =  0.0286538 V

so induced emf =  28.65 mV

3 0
3 years ago
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