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dezoksy [38]
3 years ago
8

which pole of a compass needle points north ? please give simple answer with little explaining if any :)

Physics
1 answer:
Mumz [18]3 years ago
6 0
I think the North Pole
If I understand this correctly
You might be interested in
Alicia drew a pentagon with equal side length and equal angles.Then she added red lines of symmetry to her drawing. How many lin
IRISSAK [1]
The sum of angles in a regular pentagon is
180*(5 - 2) = 540°
Each internal angle is 540/5 = 108°.

Each vertex creates a line of symmetry to the midpoint of the opposite side,
as shown in the figure.

Answer: 5 lines of symmetry.

7 0
3 years ago
PLEASE HELP!!!!
sergeinik [125]

Answer:

b

Explanation:

8 0
3 years ago
Read 2 more answers
Need help to get this question right!!
Charra [1.4K]

Answer:

16 times as strong

Explanation:

From the question given above, the following assumptions were made:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

Final force (F₂) =?

Next, we shall obtain a relationship between the force and the distance apart. This can be obtained as follow:

F = GM₁M₂ / r²

Cross multiply

Fr² = GM₁M₂

If G, M₁ and M₂ are kept constant, then,

F₁r₁² = F₂r₂²

Finally, we determine the new force as follow:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

Final force (F₂) =?

Fr² = F₂ × (¼r)²

Fr² = F₂ × r²/16

Fr² = F₂r² / 16

Cross multiply

16Fr² = F₂r²

Divide both side by r²

F₂ = 16Fr² / r²

F₂ = 16F

From the calculations made above, we can see that the new force is 16 times the original force.

Thus, the new force is 16 times stronger.

8 0
3 years ago
A point charge is placed at the center of a spherical Gaussian surface. The electricflux ΦEischangedif(a) a second point charge
Simora [160]

Answer:

(b) the point charge is moved outside the sphere

Explanation:

Gauss' Law states that the electric flux of a closed surface is equal to the enclosed charge divided by permittivity of the medium.

\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

According to this law, any charge outside the surface has no effect at all. Therefore (a) is not correct.

If the point charge is moved off the center, the points on the surface close to the charge will have higher flux and the points further away from the charge will have lesser flux. But as a result, the total flux will not change, because the enclosed charge is the same.

Therefore, (c) and (d) is not correct, because the enclosed charge is unchanged.

7 0
4 years ago
A single sports fan is capable of yelling at an intensity level of 80 decibels from a given distance. If 10,000 similar fans wer
AleksandrR [38]

Answer:

The correct answer is part 'c' 160 dB

Explanation:

When noise levels of different intensities are superimposed the resultant intensity is given by the equation

L_{avg}=20log(\frac{1}{N}\sum_{i=1}^{N}(10^{\frac{L_{i}}{20}}))\\

where,

L_{i} is the intensity of a general sound level

Since we have 10000 fans each producing sound of 80dB thus the resultant intensity is given using the above formula as

L_{avg}=20log(\frac{1}{10000}\sum_{i=1}^{10000}(10^{\frac{80}{20}}))\\

\therefore L_{eq}=160dB

7 0
3 years ago
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