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iragen [17]
4 years ago
6

(b) A 0.13−kg baseball thrown at 100 mph has a momentum of 5.9 kg · m/s. If the uncertainty in measuring the mass is 1.0 × 10−7

of the mass, calculate the uncertainty in the baseball's position.
Physics
1 answer:
polet [3.4K]4 years ago
5 0

Answer:

Δp.ΔX\geqh/4\pi

Δp = 1.0 × 10−7× 5.9 kg · m/s

     = 5,9×10^{-7}kg · m/s

Δx \geq h/ 4×\pi×m×Δv

     Δx \geq  6.626×10^{-34} J.s / 4\pi×5,9×10^{-7}kg · m/s

           \geq 8.94×10^{-29} m

Explanation:

using the Heisenbergs uncertainty principle which states that we cannot simultaneously measure with great precision both momentum and position of the particle.

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A dog walking to the right with a speed of 1.5 m/s sees a cat and speeds up with a constant rightward acceleration of magnitude
joja [24]

Answer: 8.62

Explanation: It’s correct answer:)

8 0
3 years ago
What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?
Setler [38]

Answer:

Momentum, p=7.8\times 10^{-5}\ N-m

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m

So, the momentum of the mosquito is 7.8\times 10^{-5}\ N-m.

3 0
3 years ago
If you measure the amount of work accomplished in a particular time interval, u have measured-
serious [3.7K]

Answer:

The power

Explanation:

We know that the work definition is given by the following expression:

W = F * d

where:

F = force [Newtons] [N]

d = distance [meters] [m]

W = work [Joules]

And the expression that defines the work done by unit of time is called - <u>Power</u>, therefore:

P = W/t

where:

P = power [watts] [w]

W = work [Joules] [J]

t = time [seconds] [s]

6 0
3 years ago
A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision
Nimfa-mama [501]

Answer:

Δ KE =  249158.6 kJ  

Explanation:

given data

Truck mass  M =  1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum  that is express as

Mu = (M+m) V     .......................1

put here  value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy  will be here

Δ KE =   \frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2         .................2

put here value and we get

 Δ KE = \frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2  

solve it we get

Δ KE =  249158.6 kJ  

6 0
3 years ago
Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the
Zolol [24]

Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

A) 0.10 kg is lightest among them, so it's your answer

6 0
3 years ago
Read 2 more answers
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