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iragen [17]
4 years ago
6

(b) A 0.13−kg baseball thrown at 100 mph has a momentum of 5.9 kg · m/s. If the uncertainty in measuring the mass is 1.0 × 10−7

of the mass, calculate the uncertainty in the baseball's position.
Physics
1 answer:
polet [3.4K]4 years ago
5 0

Answer:

Δp.ΔX\geqh/4\pi

Δp = 1.0 × 10−7× 5.9 kg · m/s

     = 5,9×10^{-7}kg · m/s

Δx \geq h/ 4×\pi×m×Δv

     Δx \geq  6.626×10^{-34} J.s / 4\pi×5,9×10^{-7}kg · m/s

           \geq 8.94×10^{-29} m

Explanation:

using the Heisenbergs uncertainty principle which states that we cannot simultaneously measure with great precision both momentum and position of the particle.

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REY [17]

Answer:

Explanation:

El impulso aplicado a la pelota produce una variación en su momento lineal.

J = m (V -Vo)

Conviene elegir positivo el sentido de la velocidad final.

J = 0,100 kg [40 - (- 20)] m/s = 6 kg m/s

Saludos Herminio

7 0
3 years ago
g An astronaut must journey to a distant planet, which is 189 light-years from Earth. What speed will be necessary if the astron
Butoxors [25]

Answer:

The value is v  =  2.999 *10^{8} \  m/s

Explanation:

From the question we are told that

   The time taken to travel to the planet from earth is t = 189 \ light-years

    The  time to be spent on the ship is  t_{s} =  12 \  years

Generally speed can be obtained using the mathematical relation represented below

       t_s  =  2 * t *  \sqrt{1 -  \frac{v^2}{c^2 } }

The 2 in the equation show that the trip is a round trip i.e going and coming back

=>    12 =  2 * 189 *  \sqrt{1 -  \frac{v^2}{(3.0*10^{8})^2 } }

=>     v  =  2.999 *10^{8} \  m/s

5 0
3 years ago
What is the force needed to give a .25 kg arrow an acceleration of 196m/s2?
Rzqust [24]
<span>49N is the force needed to give a .25 kg arrow an acceleration of 196m/s2. F =ma ⇒ =( 0.25kg)(196m/s2) = 49N if the arrow is shot horizontally where the applied force is entirely in the x-direction.</span>
5 0
3 years ago
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If the resistance of a circuit increases, that means that the current has to
Gnoma [55]

Answer:

If resistance increases current decreases.

Explanation:

  • Current is <em>inversely proportional</em> to the resistance.
  • from the relation given below, we can clearly see the relation between current and resistance;

                              V=IR

                              I ∝ 1/R

This relation shows that when resistance increases,current decreases.

4 0
3 years ago
A person of mass m is standing on the surface of the Earth, of mass M E . What is the acceleration that the Earth experiences du
Lana71 [14]

Answer:

a_E=\dfrac{Gm}{r^2}

Explanation:

M_E = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

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The force on the person will balance the gravitational force

M_Ea_E=\dfrac{GmM_E}{r^2}\\\Rightarrow a_E=\dfrac{Gm}{r^2}

The acceleration that the Earth will feel is a_E=\dfrac{Gm}{r^2}

7 0
3 years ago
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