c because a generator generates electricity with the use of another energy source like nuclear,solar,wind,fossil fuel,gasoline or in rare cases temperature
The impulse shared by the object equals the difference in momentum of the object. In equation form,
F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.
<h3>How to calculate thrust provided by the rocket engines is 10 kN (10 000 N).?</h3>
a)There is this impulse-momentum change equation.

We consider everything exits happen along a straight line, and gravitation does not participate.
So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.

New velocity after engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.
To learn more about Impulse-momentum, refer
brainly.com/question/20586658
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Ham is meat made from a pig =]
The one that accurately describes the products of a reaction is : B. new substances that are present at the end of a reaction
For example the process of photosynthesis transform CO2 and other nutrients into O2 and H2O
hope this helps
Answer:
Explanation:
Given
time taken 
Speed acquired in 2 sec 
Here initial velocity is zero 
acceleration is the rate of change of velocity in a given time


Distance travel in this time

where
s=displacement
u=initial velocity
a=acceleration
t=time


so Jet Plane travels a distance of 42 m in 2 s