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3 years ago

14

2 coplas o pregones inventadas por ti relacionadas con la región caribe.

1 answer:

Gnom [1K]3 years ago

7 0

I don’t speak Spanish blah blah

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At speeds over 30 mph, you should maintain a following distance of at least ________ behind the vehicle ahead of you.

ICE Princess25 [194]

At speeds over 30 mph, you should maintain a following distance of at least <u>three full seconds</u> behind the vehicle ahead of you.

As a general rule and common sense at a speed of 30 mph you can leave three full seconds so that you can achieve a prudent distance between the car you are driving and the car in front in order to be able to perform some kind of maneuver if an accident or unforeseen event occurs.

To count the full three seconds you can use the technique of counting the Mississippis as follows: Mississippi one, Mississippi two, Mississippi three.

<h3>What is an accident?</h3>

An accident is an unexpected event that generally causes damage, injury or negative consequences.

Learn more about accident at: brainly.com/question/28070413

#SPJ4

7 0

2 years ago

Water (density = 1 ´ 103 kg/m3) flows at 10 m/s through a pipe with radius 0.030 m. the pipe goes up to the second floor of the

Hatshy [7]

density of water = $1000 kg/m^3$

velocity of flow = $10 m/s$

radius of pipe = $0.030 m$

Height of second floor = $2 m$

Now we can use here Bernuoli's Equation to find the speed of water flow at second floor

$P_1 + 1/2\rho v_1^2 + \rho g h_1= P_2 + 1/2 \rho v_2^2 + \rho g h_2$

$P + 1/2 * 1000 * 10^2 + 1000* 9.8 * 0 = P + 1/2 * 1000 * v^2 + 1000*9.8*2$

$v = 7.8 m/s$

Now in order to find the radius of pipe we can use equation of continuity

$A_1 v_1 = A_2 v_2$

$\pi *0.030^2 * 10 = \pi * r^2 * 7.8$

$r = 0.034 m$

So radius of pipe at second floor is 0.034 meter

3 0

3 years ago

Calculate the mass of air in a room 5m × 4m ×2m given that the density of air is 1.3kgm-²

valentina_108 [34]

32.5 kg of air

Explanation:

To calculate the mass of the air, we use the density formula:

density = mass / volume

mass = density × volume

density of air = 1.3 kg/m³

volume = 5 × 3 × 2 = 25 m³

mass of the air = 1.3 kg/m³ × 25 m³

mass of the air = 32.5 kg

Learn more about:

density

brainly.com/question/952755

brainly.com/question/12982373

#learnwithBrainly

4 0

4 years ago

A wave is sent along the first rope transmitting a power of 57.3 W. It has a wavelength of 5.54 cm and velocity of 13.87 m/s The

Serhud [2]

Answer:

$A = 2.43*10^{-3} m$

Explanation:

power through string can be determined as shown in figure

$P = 2\pi ^2 HVA^2F^2$

Where

P = 57.3 W

V = 13.87 m/s

H = 567 g/m

we know that

$V = f *\lambda$ $\lambda = \frac{v}{f}$

therefore $P = 2\pi ^2 HVA^2(\frac{v}{f})^2$

$57.3 = \frac{2\pi ^2 * 0.567 *13.87^{3}* A^2}{(5.54*10^{-2})^2}$

$A = 2.43*10^{-3} m$

7 0

3 years ago

Calculate the moment of inertia of a skater given the following information. The skater with arms extended is approximately a cy

Bad White [126]

Answer:

The moment of inertia of a skater is : $I= 2.343 kgm^{2}$

Explanation:

we can use parallel theorem to find the moment of inertia of a skater.

Arm extended cylinder mass: $M= 52.5 kg$

Radius: $R= 0.110 m$

Length: $L= 0.900 m$

and $m=3.75 kg$

$I=\frac{1}{2} MR^{2} +[\frac{1}{2} mL^{2} +m(R+\frac{L}{2} )^{2} ]$

$I=\frac{1}{2} (52.5)(0.110)^{2} +[\frac{1}{12} (3.75)(0.900)^{2} +3.75(0.110+\frac{0.900}{2} )^{2} ]$

$I=2.343 kgm^{2}$

4 0

3 years ago