Explanation:
The formula isnt correctly written, it should state:
![a^3+b^3 = (a+b)(a^2-ab+b^2)](https://tex.z-dn.net/?f=%20a%5E3%2Bb%5E3%20%3D%20%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29%20)
You have to start from
and end in a³+b³. On your first step, you need to use the distributive property.
![(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)](https://tex.z-dn.net/?f=%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29%20%3D%20a%2A%28a%5E2-ab%2Bb%5E2%29%20%2B%20b%2A%28a%5E2-ab%2Bb%5E2%29%20)
This is equal to
![a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3](https://tex.z-dn.net/?f=a%2Aa%5E2-a%2A%28ab%29%20%2B%20a%2Ab%5E2%20%2B%20b%2Aa%5E2-b%2A%28ab%29%20%2B%20b%2Ab%5E2%20%3D%20a%5E3%20-%20a%5E2b%20%2B%20ab%5E2%20%2Bba%5E2%20-b%5E2a%20%2Bb%5E3%20)
Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.
Your answer is y=15 for your problem
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
So am I supposed to divide or multiply