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zysi [14]
3 years ago
12

A slice of cheese has a mass of 40 g and a volume of 23 cm^3. What is the density of the cheese in units of g/cm^3 and g/mL?

Physics
1 answer:
Mila [183]3 years ago
6 0

The mathematical and proportional relationship between mL and cm ^ 3 said us that 1cm ^ 3 is equivalent to 1mL.

If the density is considered as the amount of mass per unit volume we will have to

\rho = \frac{m}{V}

here,

m = mass

V = Volume

Replacing we have that

\rho = \frac{40g}{23cm^3}

\rho = 1.739g/cm^3

As 1mL = 1cm^3 we have that the density in g/mL is,

\rho = 1.739g/mL

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Explanation:

1. To graphically add vectors, use the tail-to-tip method.  Draw the first vector (it doesn't matter which), then draw the second vector where the first vector ends.  The resultant vector is from the tail of the first vector to the tip of the second vector.

This graph shows two ways to get the resultant: A + B or B + A.

desmos.com/calculator/bqhcclhhqc

2. To algebraically add vectors, split each vector into x and y components.

Aₓ = 5.0 cos 45 = 3.5

Aᵧ = 5.0 sin 45 = 3.5

Bₓ = 2.0 cos 180 = -2.0

Bᵧ = 5.0 sin 180 = 0

The components of the resultant vector are the sums of the components of A and B.

Cₓ = 3.5 + -2.0 = 1.5

Cᵧ = 3.5 + 0 = 3.5

The magnitude of the resultant vector is found with Pythagorean theorem, and the direction is found with tangent.

C = √(Cₓ² + Cᵧ²) ≈ 3.9 m/s

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