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zysi [14]
3 years ago
12

A slice of cheese has a mass of 40 g and a volume of 23 cm^3. What is the density of the cheese in units of g/cm^3 and g/mL?

Physics
1 answer:
Mila [183]3 years ago
6 0

The mathematical and proportional relationship between mL and cm ^ 3 said us that 1cm ^ 3 is equivalent to 1mL.

If the density is considered as the amount of mass per unit volume we will have to

\rho = \frac{m}{V}

here,

m = mass

V = Volume

Replacing we have that

\rho = \frac{40g}{23cm^3}

\rho = 1.739g/cm^3

As 1mL = 1cm^3 we have that the density in g/mL is,

\rho = 1.739g/mL

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Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el
rewona [7]

Answer:

a) x = 0.200 m

b)E = 3.84*10^{-4} N/C

Explanation:

q_1 = 21.0\mu C

q_1 = 47.0\mu C

DISTANCE BETWEEN BOTH POINT CHARGE = 0.5 m

by relation for electric field we have following relation

E = \frac{kq}{x}^2

according to question E = 0

FROM FIGURE

x is the distance from left point charge where electric field is zero

\frac{k21}{x}^2 = \frac{k47}{0.5-x}^2

solving for x we get

\frac{0.5}{x} = 1+ \sqrt{\frac{47}{21}}

x = 0.200 m

b)electric field at half way mean x =0.25

E =\frac{k*21*10^{-6}}{0.25^2} -\frac{k*47*10^{-6}}{0.25^2}

E = 3.84*10^{-4} N/C

6 0
3 years ago
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Which describes an atom that has fewer neutrons than protons and more electrons than protons?
aleksklad [387]

Answer:

negative ion

Explanation:

An atom that has fewer neutrons than protons and more electrons than protons is a negative ion.

The positively charged particles in an atom are the protons

The negatively charged particles in an atom are the electrons.

  The charge an atom carries depends on the balance between the number of protons and electrons in an atom.

  • When the number of protons is more than the number of electrons, the atom is positively charged.
  • When the number of electrons is more than the number of protons, the atom is negatively charged.
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3 years ago
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What does democratized knowledge mean?
lutik1710 [3]
I think it’s A I got that off the information I got in the internet
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A box of mass 64 kg is at rest on a horizontal frictionless surface. A constant horizontal force F~ then acts on the box and acc
iren2701 [21]

Answer:

The correct answer is;

The magnitude of the force is 35.12 N

Explanation:

To solve the question, we note that the friction is zero and the force causes motion of a stationary mass

One of the equations of motion is required such as

v² = u² + 2× a× s

Where

v = Final velocity = 5.93 m/s

u = Initial velocity = 0 m/s , object at rest

a = acceleration

s = distance moved = 32 meters

But v = Distance/Time = 32 m /5.4 s = 5.93 m/s

Therefore

5.93² = 2×a×32

or a = 35.12/ 64 = 0.55 m/s²

Therefore Force F = Mass m × Acceleration a

Where mass m = 64 kg

Therefore F = 64 kg×0.55 m/s² = 35.12 N

3 0
3 years ago
2. A motor with a resistance of 32 is connected to a voltage source. Four amps of current
FromTheMoon [43]

Answer:128

Explanation:

solve by V=IR formula

V=32 * 4

V= 128

3 0
3 years ago
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