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zysi [14]
3 years ago
12

A slice of cheese has a mass of 40 g and a volume of 23 cm^3. What is the density of the cheese in units of g/cm^3 and g/mL?

Physics
1 answer:
Mila [183]3 years ago
6 0

The mathematical and proportional relationship between mL and cm ^ 3 said us that 1cm ^ 3 is equivalent to 1mL.

If the density is considered as the amount of mass per unit volume we will have to

\rho = \frac{m}{V}

here,

m = mass

V = Volume

Replacing we have that

\rho = \frac{40g}{23cm^3}

\rho = 1.739g/cm^3

As 1mL = 1cm^3 we have that the density in g/mL is,

\rho = 1.739g/mL

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Because the Earth rotates about its axis, a point on the equator experiences a centripetal acceleration of 0.033 7 m/s2, while a
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Answers:

a) F_{g}=735 N and n=732.47 N, hence F_{g} > n

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According to this (1) is rewritten as:

n_{equator}-mg=-m a_{c} (2)

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n_{equator}=m(-a_{c}+g) (4)

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Since F_{c-poles}=0 (8) is rewritten as:

n_{poles}=F_{g} (9)

n_{poles}=m g (10)

n_{poles}=(75 kg)(9.8 m/s^{2})=735 N (11)

So, the apparent weight of the person at the poles is 735 N and at the equator is 732.47 N

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