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nexus9112 [7]
3 years ago
12

A store pays $10 for a bracelet the markup is 115%

Mathematics
1 answer:
Arada [10]3 years ago
8 0
The original price was 8.50 dollars<span />
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Im not good with least to greatest in fractions, Please help me
tiny-mole [99]

Answer:

From least to greatest it is -5/2, -2, then 1.7

Step-by-step explanation:

First by process of elimination, 1.7 is the only positive number, so it is the greatest number compared to the other two.

Now we are left with -2 and -5/2.

We can rewrite -2 as -\frac{2}{1} , as any number by itself itself is the number over 1.

Then we need to find the common denominator for both fractions, meaning they must share the same bottom number.

The 1 in the denominator can be multiplied by 2 to get a denominator of 2 , the same as the denominator for -\frac{5}{2}.

Since the denominator is multiplied by 2, the numerator also has to be multiplied by 2:

-\frac{2}{1} *\frac{2}{2}=-\frac{4}{2}

Now since both fractions share the same denominator, we can compare them by their numerators. 5 is greater than 4, but we must keep in mind that these are negative. The larger the negative number, the smaller the value.

So when comparing -4/2 and -5/2, -5/2 is smaller.

So our final answer from least to greatest is -5/2, -2, then 1.7

8 0
3 years ago
Find the complex conjugate of z1 of z1=8+i
kakasveta [241]

Answer:

this is just math jargon... a conjugate is the same numbers but with an opposite sign.. got it?

Step-by-step explanation:

z1' ( the prime is often used for conjuates it's also used in calculus but later)

Z1' =8-i    

8 0
3 years ago
Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train tra
stepan [7]

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor  =?

Solution:

The speed of the train A = \frac{Distance}{time}

The speed of train A  =\frac{175}{4}

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5  miles per hours

Train A travels faster

Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}

rate  = \frac{43.75}{43.5}

rate  =1.01

7 0
3 years ago
Given: Triangles ABC and DBC are isosceles, m∠BDC = 30°, and m∠ABD = 155°. Find m∠ABC, m∠BAC, and m∠DBC.
just olya [345]
∠BDC=30, so ∠CBD + ∠BCD=180-30=150
ΔDBC is isosceles, so ∠CBD=∠BCD=half of 150=75
∠ABC=∠ABD-∠CBD=155-75=80
ΔABC is isosceles, so ∠ABC=∠ACB=80
∠BAC=180-80-80=20
7 0
3 years ago
Part 1
svetlana [45]

Answer:

A: This polynomial has a degree of 2 , so the equation 12x2+5x−2=0 has two or fewer roots.

B: The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots.

Step-by-step explanation:

f(x) = 12x^2 + 5x - 2.

Since this is a quadratic equation, or a polynomial of second degree, one can easily conclude that this equation will have at most 2 roots. At most 2 roots mean that the function can have either 2 roots at maximum or less than 2 roots. Therefore, in the A category, 2nd option is the correct answer (This polynomial has a degree of 2 , so the equation 12x^2 + 5x − 2 = 0 has two or fewer roots).

To find the roots of f(x), set f(x) = 0. Therefore:

12x^2 + 5x - 2 = 0. Solving the question using the mid term breaking method shows that 12*2=24. The factors of 24 whose difference is 5 are 8 and 3. Therefore:

12x^2 + 8x - 3x - 2 = 0.

4x(3x + 2) -1(3x+2) = 0.

(4x-1)(3x+2) = 0.

4x-1 = 0 or 3x+2 = 0.

x = 1/4 or x = -2/3.

It can be seen that f(x) has two distinct real roots. Therefore, in the B category, 1st Option is the correct answer (The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots)!!!

8 0
3 years ago
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