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3 years ago

What element is being oxidized in the following redox reaction?

Chemistry

1 answer:

gregori [183]3 years ago

4 0

Answer:

C is the element thats has been oxidized.

Explanation:

MnO₄⁻ (aq) + H₂C₂O₄ (aq) → Mn²⁺ (aq) + CO₂(g)

This is a reaction where the manganese from the permanganate, it's reduced to Mn²⁺.

In the oxalic acid, this are the oxidation states:

H: +1

C: +3

O: -2

In the product side, in CO₂ the oxidation states are:

C: +4

O: -2

Carbon from the oxalate has increased the oxidation state, so it has been oxidized.

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Many common liquids have boiling points that are less than 110°C, whereas most metals are solids at room temperature and have mu

Semmy [17]

Answer:

1. 315.4 K

2. 1560 °C

Explanation:

To convert from celsius to Kelvin, the following formula can be used:

T(K) = T(°C) + 273

Where:

T(K) => Temperature in Kelvin

T(°C) => Temperature in degree celsius

1. Determination of the temperature in Kelvin.

Temperature (T) in °C = 42.4 °C.

Temperature (T) in K =?

T(K) = T(°C) + 273

T(K) = 42.4 °C + 273

T(K) = 315.4 K

2. Determination of the temperature in degree Celsius.

Temperature (T) in K = 1833 K

Temperature (T) in °C =?

T(K) = T(°C) + 273

1833 = T(°C) + 273

Collect like terms

T(°C) = 1833 – 273

T(°C) = 1560 °C

7 0

2 years ago

What type of system is best used to observe conservation of matter because all of the mass stays in one place?

melamori03 [73]

Answer:

Hello, There!

<em>What type of system is best used to observe conservation of matter because all of the mass stays in one place?</em>

<em />

A closed system Would be The Correct Answer!

Explanation:

In a closed system, matter does not enter or leave And it Says In one place.

Therefore, making A Closed System the Correct Answer.

7 0

2 years ago

What is the answer to this chemistry question?

olga_2 [115]

Answer:

The answer to your question is remplacement double

Explanation:

Data

Lead (II) nitrate = Pb(NO₃)₂

Potassium iodide = KI

Process

1.- Write the balanced chemical reaction

Pb(NO₃)₂ + 2KI ⇒ PbI₂ + 2KNO₃

2.- Conclusion

This is a remplacement double reaction because there are two reactants that interchange cations and the products are a combination of the reactants.

5 0

3 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

2 years ago

A solution is made by dissolving 4.0 moles of sodium chloride (NaCl) in 2.05 kilograms of water. If the molal boiling point cons

kozerog [31]

Properties of a solution that depend only on the ratio of the number of particles of solute and solvent in the solution are known as colligative properties. For this problem, we use boiling point elevation concept.

ΔT(boiling point) = (Kb)mi
ΔT(boiling point) = (0.51 C-kg / mol )(4.0 mol / 2.05 kg ) (2)
ΔT(boiling point) = 1.99 C

T(boiling point) = 101.99 C

4 0

2 years ago