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Shkiper50 [21]
3 years ago
6

If you want to increase the gravitational force between two objects; would you rather double the mass of one object or halve the

distance between them?
Select one:
a. Double the mass of one object
b. Halve the distance between them
c. Both would have the same effect
d. There is not enough information to determine
Physics
1 answer:
Step2247 [10]3 years ago
5 0

To solve this problem we will apply the concepts related to the Force of gravity from Newtonian theory for which it is necessary to

F = \frac{GMm}{R^2}

Where,

G = Gravitational universal constant

M = Mass of Earth

m = mass of Object

x = Distance between center of mass of the objects.

From this equation we can observe that the Force is inversely proportional to the squared distance between the two objects. The greater the distance, the lower the force of gravity and vice versa.

F \propto \frac{1}{R^2}

If you want to increase the force of gravity, you need to reduce the distance of the two. Therefore the correct option is B. Talk to the distance between them.

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Use the diagram to answer the questions below.
svet-max [94.6K]

Answer:

1. because of the tilted axis of earth the seasons in northern hemisphere are the exact opposite of the southern. because the sunrays reaches the earth an different points and when the earth moves around the sun it changes the hemisphere which is tilted to the sun.

2. the northern hemisphere is in Winter and the southern in summer. because the southern is tilted to the sun and the northern not so less sunrays reaches the northern hemisphere.

I'm sorry my explanation are bad

4 0
3 years ago
Force X has a magnitude of 1260 ​pounds, and Force Y has a magnitude of 1530 pounds. They act on a single point at an angle of 4
weeeeeb [17]

Answer:

Fe= 2579.68 P

α= 24.8°

Explanation:

Look at the attached graphic

we take the forces acting on the x-y plane and applied at the origin of coordinates

FX = 1260 P , horizontal (-x)

FY = 1530  P , forming 45° with positive x axis

x-y components FY

FYx= - 1530*cos(45)° = - 1081.87 P

FYy= -  1530*sin(45)° = - 1081.87 P

Calculation of the components of net force (Fn)

Fnx= FX + FYx

Fnx= -1260 P -1081.87 P

Fnx= -2341.87 P

Fny=FYy

Fny= -1081.87 P

Calculation of the components of equilibrant force (Fe)

the x-y components of the  equilibrant force are equal in magnitude but in the opposite direction to the net force components:

Fnx= -2341.87 P, then, Fex= +2341.87 P

Fny=  -1081.87 P P, then, Fex= +1081.87 P

Magnitude of the equilibrant (Fe)

F_{n} = \sqrt{(F_{nx})^{2} +(F_{ny})^{2}  }

F_{e} =\sqrt{(2341.87)^{2}+(1081.87)^{2}  }

Fe= 2579.68 P

Calculation of the direction of  equilibrant force (α)

\alpha =tan^{-1} (\frac{F_{ny} }{F_{nx} } )

\alpha =tan^{-1} (\frac{1081.87 }{2341.87} )

α= 24.8°

Look at the attached graphic

6 0
3 years ago
A straight vertical wire carries a current of 1.0 A into the page in a region where the magnetic field strength is 0.60 T. What
Advocard [28]

Answer:

force on the wire of section  cm will be 6\times 10^{-3}N

Direction of force on the wire will be in south direction        

Explanation:

We have given current in the wire i = 1 A

Magnetic field strength B = 0.6 T

We have to find the force on 1 cm section of the wire so l = 1 cm = 0.01 m

Force on the wire containing current is equal to

F=iBL

F=1\times 0.6\times 0.01=6\times 10^{-3}N

So force on the wire of section  cm will be 6\times 10^{-3}N

Direction of force on the wire will be in south direction

5 0
3 years ago
A 10 m long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 30 m/s when a 68
timama [110]

Answer:

 v = 30.39 m/s

Explanation:

given,

mass of glider,M = 680 Kg

mass of the skydiver, m = 68 Kg

horizontal velocity,V = 30 m/s

when skydiver releases, velocity,v = 30 m/s

velocity if the glider,v' =  ?

use the conservation of momentum

M V = m' v' +  m v

m' = 680-68 = 612 Kg

680 x 30 = 612 x v + 60 x 30

612 v = 18600

 v = 30.39 m/s

since the skydiver's speed will be the same as before release

The glider should continue to travel at 30.39 m/s since there are no external forces acting on it

5 0
3 years ago
If the area of a concrete slap weighing 300n is 400cm2 ,how much pressure can it apply when kept on the ground
aleksklad [387]

Answer:

7500 N/m²

Explanation:

From the question given above, the following data were obtained:

Force (F) = 300 N

Area (A) = 400 cm²

Pressure (P) =?

Next, we shall convert 400 cm² to m². This can be obtained as follow:

1×10⁴ cm² = 1 m²

Therefore,

400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²

400 cm² = 0.04 m²

Finally, we shall determine the pressure. This can be obtained as follow:

Force (F) = 300 N

Area (A) = 0.04 m²

Pressure (P) =?

P = F/A

P = 300 / 0.04

P = 7500 N/m²

3 0
3 years ago
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