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fredd [130]
2 years ago
15

Abc Which excerpt from an essay about higher education most clearly shows an example of logos? According to recent studies, more

women than ever are attending four-year colleges. In fact, 36.6 percent of women attended college in 2019, compared to 35.4 percent of men. O When I went to college in 1994, I was the first person in my family to do so. My mother stood in my dorm room, surrounded by boxes of clothes and trinkets and holding back tears. O I was in awe of my sociology professor, who had studied the historical impacts of food in African American culture for 10 years. She spoke with such passion and energy that it was difficult to take your eyes off her. O Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork. Mark this and return Save and Exit Next Submit​
Chemistry
1 answer:
Naddik [55]2 years ago
8 0

The excerpt from an essay about higher education that most clearly shows an example of logos is:

  • Option d:  Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.

<h3>What is Logos?</h3>

The Logos Definition is one that is often argued by a lot of people as people tends to appeal to others emotions and some other times, people do appeal to one's' ethics or morals.

The term logos is a term that connote the use of logic. It also includes the use of deductive reasoning to get to a conclusion.

The excerpt from an essay about higher education that most clearly shows an example of logos is:

  • Option d:  Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.

Option d is correct because it shows the cause and its effect.

Learn more about logos from

brainly.com/question/4656950

#SPJ1

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Answer:

1/3p0

Explanation:

The combined gas law:

P1V1/T1 = P2V2/T2, where P, V and T are Pressure, Volume, and Temperature.  Temperature must always be in Kelvin.  The subscriopts 1 and 2 are for initial (1) and final (2) conditions.

In this case, temperature is constant (adiabatically). V1 = 2.0L and V2 = 6.0L.  I'll assume P1 = p0.

Rearrange the combined gas law to solve for final pressure, P2:

P1V1/T1 = P2V2/T2

P2 = P1*(V1/V2)*(T2/T1)  [Note how I've arranged the volume and temoperature terms - as ratios.  This helps us understand what the impact of raising or lowering one on the variables will do to the system].

No enter the data:

P2 = P1*(V1/V2)*(T2/T1):  [Since T2 = T1, the (T2/T1) terms cancels to 1.]

P2 = p0*(2.0L/6.0L)*(1)

P2 = (1/3)p0

The final pressure is 1/3 the initial pressure.

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