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timurjin [86]
3 years ago
7

A balloon containing 0.10 moles of gas has a volume of 2.00 liters. If temperature and pressure remain constant, the new volume

will be 3.00 liters when you add 0.15 moles of gas to the balloon.
TRUE
FALSE
BRAINLIEST
Chemistry
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

In a balloon with a volume of 3.00 L gas, there is a total of 0.15 moles of gas.

If we add 0.15 moles to a balloon containing 0.10 moles, the new volume is 5 L

Explanation:

Step 1: Data given

Number of moles = 0.10 moles of gas

Volume of gas= 2.00 L

New volume = 3.00 L

Step 2: Calculate new number of moles

Avogadro's law says:

n1/V1 = n2/V2

⇒ with n1 = the number of moles of gas = 0.10 moles

⇒ with V1 = the volume of gas in the balloon = 2.00 L

⇒ with n2 = the number of moles when then volume changed to 3.00L

⇒ with V2 = the new volume = 3.00 L

0.10 mol / 2.00 L = n2 / 3.00 L

n2 = (0.10 * 3.00)/2.00

n2 = 0.15 moles

When adding 0.15 moles of gas to the balloon, the total number of moles is 0.25 moles, the total volume will be:

0.10 mol / 2.00 L = 0.25 moles / V2

V2 = 5 L

In a balloon with a volume of 3.00 L gas, there is a total of 0.15 moles of gas.

If we add 0.15 moles to a balloon containing 0.10 moles, the new volume is 5 L

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Explanation:

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<em>How much heat will be given off if molar quantities of 2-methylheptane react according to the following equation? 2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O</em>

In this equation we have 2 moles of C₈H₁₈. So,

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3 0
3 years ago
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