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3 years ago

How is matter conserved in the carbon cycle?

Chemistry

2 answers:

Sholpan [36]3 years ago

7 0

B. Carbon changes from one form to another, but the total amount of carbon remains the same.

wlad13 [49]3 years ago

6 0

Answer:

Explanation:

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A solid with a low melting point is most likely

Reil [10]

A solid with a low melting point is most likely is held together by covalent bonds. Examples are hydrocarbons, ice, sugar and sulfur. The have low melting points because of the covalent bonds . It do not form crystals therefore can easily be broken. The attractions are weak.

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3 years ago

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100 POINTS! HELP ME IF YOU LOVE JESUS!

mr Goodwill [35]

I only got 50 points (which is not 100). :-)

Look at the graph. At 80 °C, about 38 g of solute is able to dissolve, and that’s for ever 100 g of water. That means that for every 150 grams of water, 57 grams of solute can dissolve (38/2 = 19 + 38 = 57 g) at 80 °C. Since 57 g is greater than 55 g, all for he sodium chloride should dissolve in 150 g of water at 80 °C - you can put all of that into a “mathematical explanation”.

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2 years ago

A general term for a chemical which accelerates a reaction without becoming chemically involved is called a catalyst. true false

BARSIC [14]

As long as the chemical is not used up in the reaction the answer is true

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3 years ago

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What is the molarity of a solution composed

Neporo4naja [7]

Answer:

0.0845 M

Explanation:

First we convert 4.27 grams of potassium iodide into moles, using its molar mass:

Molar Mass of KI = 166 g/mol

4.27 g ÷ 166 g/mol = 0.0257 mol

Now we calculate the molarity of the solution, using the number of moles and the given volume:

Molarity = moles / liters

Molarity = 0.0257 mol / 0.304 L = 0.0845 M

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3 years ago

A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el

icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T $_2$ ),

P $_1$ V $_1$ / T $_1$ = P $_2$ V $_2$ / T $_2$ ,

T $_2$ = P $_2$ V $_2$ T $_1$ / P $_1$ V $_1$ ,

T $_2$ = 0.73 atm $*$ 1.8 L $*$ 298.15 K / 1 atm $*$ 1.2 L = ( 0.73 $*$ 1.8 $*$ 298.15 / 1 $*$ 1.2 ) K = 326.47425 K,

T $_2$ = 326.47425 K = 53.32425 C

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3 years ago