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2 years ago

How is matter conserved in the carbon cycle?

Chemistry

2 answers:

Sholpan [36]2 years ago

7 0

B. Carbon changes from one form to another, but the total amount of carbon remains the same.

wlad13 [49]2 years ago

6 0

Answer:

Explanation:

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Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

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2 years ago

The following structure depicts three C atoms, two Br atoms, and eight H atoms,

Darya [45]

Answer: False

Explanation: There are four carbon atoms , eight hydrogen atoms and two Bromine atoms.

As the carbon forms four covalent bonds, every carbon must have four bonds and thus the formula of the compound is $BrCH_2-CH(Br)-CH_2-CH_3$ .

IUPAC name of the compound is 1,2 di-bromobutane. As the carbon chain is 4 atoms long the word used is but and all the bonds are single bonds, thus the suffix used is ane.

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Explanation:

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