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Natali5045456 [20]
3 years ago
12

John recently suffered a blow to his head. Since then, he finds it difficult to comprehend what others say to him. He also finds

it difficult to express his thoughts and cannot seem to find the right words to say while speaking. However, he can speak freely with proper syntax. In this scenario, John is most likely suffering from _______.
Physics
1 answer:
katovenus [111]3 years ago
6 0

Answer: ​Wernicke's aphasia

Explanation:

John recently suffered a blow to his head. Since then, he finds it difficult to comprehend what others say to him. He also finds it difficult to express his thoughts and cannot seem to find the right words to say while speaking. However, he can speak freely with proper syntax. In this scenario, John is most likely suffering from Wernicke's aphasia.

Wernicke's aphasia occurs when the leftward side of the middle of the brain is damaged or has been altered. An individual who suffers from Wernicke's aphasia will have difficulty in speaking in meaningful and coherent sentences or may have difficulty in understanding the speech of others.

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A box sits on the back of a flatbed truck. If the coefficient of static friction between the box and the truck bed is μs = 0.400
slava [35]

Answer:

28,699m

Explanation:

The force to make the box move should be <u>μs.N=μs.m.g=m.</u><u>|</u><u>a</u><u>|</u>

then,

|a|=μs.g

Being

μs coefficient of static friction,

N the force made by the truck on the box caused by the gravity force,

m the mass,

g the acceleration of gravity

and a the acceleration of the truck.

x = v \times t  +  \frac{1}{2} \times a \times   {t}^{2}

as the truck is stopping, the acceleration is negative. then,

x = v \times t  -  \frac{1}{2} \times  |a| \times   {t}^{2}

|a|  = v  \div  t \\ t = v \div   |a|

x = v \times (v \div   |a| ) -  \frac{1}{2} \times  |a| \times   {(v \div   |a|)}^{2}

x = v \times (v \div  μs.g ) -  \frac{1}{2} \times  |a| \times   {(v \div   μs.g)}^{2}

x =   \frac{{v}^{2}}{μs \times g} -  \frac{1}{2} \times  \frac{{v}^{2}}{μs \times g} \\ x = \frac{1}{2} \times  \frac{{v}^{2}}{μs \times g} \\ x = 0.5 \times  \frac{{(15m/s) }^{2} }{0.4 \times 9.8m/ {s}^{2} }  = 28.699m

28,699m

7 0
2 years ago
The design phase in which a building project's basic functional requirements are first laid out (square footage, utility and equ
VikaD [51]

Answer:

e. design programming

Explanation:

The planning techniques are responsible for structuring the tasks to be performed within the project, defining the duration and the order of execution of the same, while the programming techniques try to organize the activities so that the logical temporal relationships between them, determining the calendar or the moments of time in which each one must be realized. The programming must be consistent with the objectives pursued and respect existing restrictions (resources, costs, workloads).

The programming therefore consists in setting, in an approximate way, the moments of beginning and termination of each activity. Some activities may have slack and others are critical activities (fixed over time).

STEPS:

Build a time diagram (moments of beginning and slack of activities).

Establish the times of each activity.

Analyze project costs and adjust clearances (minimum cost project).

7 0
3 years ago
Noble gases, such as argon and neon, are known for being extremely non-reactive. Neon and argon are non-reactive because they A.
Greeley [361]
B. have eight electrons in their outer shell
3 0
3 years ago
Read 2 more answers
A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.2
leva [86]

Answer:

Tension = 0.012 N

Explanation:

If the black widow spider is hanging vertically motionless from the ceiling above. Then, the weight of the spider must be balancing the tension in the spider web. Therefore,

Tension = Weight

Tension = mg

where,

m = mass of spider = 1.27 g = 0.00127 kg

g = acceleration due to gravity = 9.8 m/s²

Therefore,

Tension = (0.00127 kg)(9.8 m/s²)

<u>Tension = 0.012 N</u>

8 0
3 years ago
Which is the quickest way to accurately take your heart rate
Thepotemich [5.8K]
I would say by putting two fingers under your chin or putting two fingers on the back of your wrist, hope i helped ! :)
3 0
3 years ago
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