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mariarad [96]
2 years ago
6

A _____________ is defined as a push or pull that acts on objects and, in some instances, changes their position.

Physics
2 answers:
Shkiper50 [21]2 years ago
6 0
Force !!!!!!!!!!!!!!!!!!!!!!!!!!!
madreJ [45]2 years ago
5 0
Its a force for suree
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A professional cyclist rides a bicycle that is 92 percent efficient. For every 100 joules of energy he exerts as input work on t
emmainna [20.7K]
Efficiency =  Work Output / Work Input

92%  =  Work Output / 100

0.92 =   Work Output / 100

Work Output = 0.92 * 100

Work Output  = 92 joules.
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3 years ago
In a river, sediment is deposited _____. on the inside bends on the outside bends by fast moving water by oxbows
N76 [4]
Hey There!

Your answer is on the inside bends!

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If you need anymore help with your work feel free to ask me!

Hope this Helps!
3 0
3 years ago
15. What is a thermograph?
Genrish500 [490]

Answer: A device that uses infrared sensors.

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8 0
3 years ago
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A ball thrown with 50N of force accelerates at 25 m/s2.  What is the mass of the ball?
MrRissso [65]
F=ma
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7 0
3 years ago
Ask Your Teacher Suppose the roller coaster below(h1 = 36 m, h2 = 13 m, h3 = 30) passes point A with a speed of 1.00 m/s. If the
Oliga [24]

Answer:

The answer to the question is

The roller coaster will reach point B with a speed of 14.72 m/s

Explanation:

Considering both kinetic energy KE = 1/2×m×v² and potential energy PE = m×g×h

Where m = mass

g = acceleration due to gravity = 9.81 m/s²

h = starting height of the roller coaster

we have the given variables

h₁ = 36 m,

h₂ = 13 m,

h₃ = 30 m

v₁ = 1.00 m/s

Total energy at point 1 = 0.5·m·v₁² + m·g·h₁

= 0.5 m×1² + m×9.81×36

=353.66·m

Total energy at point 2 = 0.5·m·v₂² + m·g·h₂

= 0.5×m×v₂² + 9.81 × 13 × m = 0.5·m·v₂² + 127.53·m

The total energy at 1 and 2 are not equal due to the frictional force which must be considered

Total energy at point 2 = Total energy at point 1 + work done against friction

Friction work = F×d×cosθ = (\frac{1}{5} × mg)×60×cos 180 = -117.72m

0.5·m·v₂² + 127.53·m = 353.66·m -117.72m

0.5·m·v₂² = 108.41×m

v₂² = 216.82

v₂  =  14.72 m/s

The roller coaster will reach point B with a speed of 14.72 m/s

8 0
3 years ago
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