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Crank
3 years ago
12

Point charge A with a charge of +4.00 μC is located at the origin. Point charge B with a charge of +7.00 μC is located on the x

axis at x = 7.00 cm. And point charge C with a charge of +3.00 μC is located on the y axis at y = 6.00 cm. What is the direction of the net force exerted on charge A by the others?
Physics
2 answers:
never [62]3 years ago
8 0

Answer:

210.3 degrees

Explanation:

The net force exerted on charge A = 59.5 N

Use the x and y coordinates of net force to get the direction

arctan (y/x)

Dominik [7]3 years ago
3 0

Answer:

F = -51.357i -29.958j

abs(F) = 59.45 N

Explanation:

To solve the problem we use coulomb's law with vectorial notation, F = q1*q2/(4*pi*eo*r^2) where q1 and q2 are the charges and r is the distance between them:

Point B exerts a force on A in '-i' direction  

Point C exerts a force on A in '-j' direction  

Fba = 4*7/(4*pi*eo*0.07^2) = 51.357N

Fca = 4*3/(4*pi*eo*0.06^2) = 29.958N  

F = -51.357i -29.958j

abd(F) = 59.45 N

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If A and B are two objects with masses 6 kg and 34 kg respectively then
Mademuasel [1]

Answer:

the object B has more mass (= 34 kg) than the object A (= 6 kg)................................ ᕦ( ᐛ )ᕡ

4 0
3 years ago
The elevator accelerates upward (in the positive direction) from rest at a rate of 1.95 m/s2 for 2.15 s. Calculate the tension i
sammy [17]

The mass is missing. The mass of the elevator is 1650 kg.

Answer:

The tension in the cable is 19387.5 N.

Explanation:

Given:

Initial velocity of the elevator (u) = 0 m/s

Acceleration in the upward direction (a) = 1.95 m/s²

Time taken by the elevator (t) = 2.15 s

Mass of the elevator and persons (m) = 1650 kg

Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

So, net force on the elevator is given as:

F_{net}=T-mg

Now, from Newton's second law, net force equals mass times acceleration.

F_{net}=ma\\\\T-mg=ma\\\\T=m(g+a)

Plug in the given values and solve for 'T'. This gives,

T=1650\ kg(9.8+1.95)\ m/s^2\\\\T=1650\times11.75\ N\\\\T=19387.5\ N

Therefore, the tension in the cable is 19387.5 N.

3 0
4 years ago
A 25 kg rock falls for 2.7 seconds. How many meters tall was the building?
sertanlavr [38]

Answer:

35.7m

Explanation:

Given parameters:

Mass of rock  = 25kg

Time of fall  = 2.7s

Unknown:

Height of the building = ?

Solution:

To solve this problem, we will use one of the motion equations;

     S  = ut + \frac{1}{2} gt²

S is the height

u is the initial velocity  = 0m/s

t is the time

g is the acceleration due to gravity

      S = (0 x 2.7) +  \frac{1}{2} x 9.8 x 2.7²  = 35.7m

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A 50kg object on earth weighs 81.67 on the moon
5 0
4 years ago
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1200 meters is less than 1 kilometer
SashulF [63]
<span>1200 meters is less than 1 kilometer 
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4 0
4 years ago
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