nindy thousand five hundred and twenty three. Hope this helps!
A + b = d+c
<span>a - b = e - c </span>
The b and c cancel out.
<span>2a = d+e </span>
<span>a = (d+e)/2 </span>
(x, y ) → (- 1, 3 )
The solution to the system of equations is the point of intersection of the 2 lines
From the graph, that is (x, y ) → ( - 1, 3 )
We can confirm by solving algebraically
Since both equations express y in terms of x we can equate the right sides
- x + 2 = - 6x - 3 ( add 6x to both sides )
5x + 2 = - 3 ( subtract 2 from both sides )
5x = - 5 ( divide both sides by 5 )
x = - 1
substitute x = - 1 into either of the 2 equations for y-coordinate
y = - x + 2 = 1 + 2 = 3
solution is (x, y ) → (- 1, 3 )
If he travels 5/2 miles in 15 mins, then in 1 min he will travel 5/2 ÷ 15 = 1/6 miles and it will take him 15 ÷ 5/2 = 6 mins to travel 1 mile.
![z=2x^4+8x \\ dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\ \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\ = 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}= \left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648](https://tex.z-dn.net/?f=%20z%3D2x%5E4%2B8x%20%5C%5C%0Adz%3D%288x%5E3%2B8%29%5C%20dx%3D8%28x%5E3%2B1%29%5C%20dx%20%5C%5C%0A%0A%20%5Cint%5Climits%5E0_%7B-1%7D%20%7B%282x%5E4%2B8x%29%5E3%2A%284x%5E3%2B4%29%7D%20%5C%2C%20dx%20%3D4%2A%20%5Cint%5Climits%5E0_%7B-6%7D%20%7B%20%5Cdfrac%7Bz%5E3%7D%7B2%7D%7D%20%5C%2C%20dz%20%5C%5C%0A%3D%202%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D%0A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D0-648%3D-648)
