Taking into account the scientific notation, the result of the subtraction is -4.20689×10⁻².
<h3>Scientific notation</h3>
Scientific notation is a quick way to represent a number using powers of base ten, where the numbers are written as a product:
a×10ⁿ
where:
- a is a real number greater than or equal to 1 and less than 10, to which a decimal point is added after the first digit if it is a non-integer number.
- n is an integer, which is called an exponent or an order of magnitude. Represents the number of times the comma is shifted. It is always an integer, positive if it is shifted to the left, negative if it is shifted to the right.
<h3>Subtraction in scientific notation</h3>
When the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found. In this case, the highest exponent is -2.
Then all the values are expressed as a function of the base 10 exponent with the highest exponent. In this case: 3.11×10⁻⁵= 0.00311×10⁻²
Taking the quantities to the same exponent, all you have to do is subtract what was previously called the number "a". In this case:
0.00311×10⁻² - 4.21×10⁻²= (0.00311 - 4.21)×10⁻²= -4.20689×10⁻²
Finally, the result of the subtraction is -4.20689×10⁻².
Learn more about operations in scientific notation:
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Answer:
Resonance hybrid: A weighted average of all significant resonance contributors depicting the true electronic structure of a molecule.
Explanation:
Translation: Híbrido de ressonância: uma média ponderada de todos os contribuintes de ressonância significativos, representando a verdadeira estrutura eletrônica de uma molécula.
Answer:
209.3 Joules require to raise the temperature from 10 °C to 15 °C.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m × c × ΔT
Given data:
mass of water = 10 g
initial temperature T1= 10 °C
final temperature T2= 15 °C
temperature change =ΔT= T2-T1 = 15°C - 10°C = 5 °C
Energy or joules added to increase the temperature Q = ?
Solution:
We know that specific heat of water is 4.186 J/g .°C
Q = m × c × ΔT
Q = 10 g × 4.186 J/g .°C × 5 °C
Q = 209.3 J
0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.
Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions.
The balanced neutralization equation is:
NaOH(aq) + KHC₈H₄O₄(aq) ⇒ KNaC₈H₄O₄(aq) + H₂O(l)
- Step 1: Calculate the reacting moles of KHP.
0.212 g of KHP react. The molar mass of KHP is 204.22 g/mol.
0.212 g × 1 mol/204.22 g = 1.04 × 10⁻³ mol
- Step 2: Determine the reacting moles of NaOH.
The molar ratio of NaOH to KHP is 1:1.
1.04 × 10⁻³ mol KHP × 1 mol NaOH/1 mol KHP = 1.04 × 10⁻³ mol NaOH
- Step 3: Calculate the molarity of NaOH.
1.04 × 10⁻³ moles of NaOH are in 35.00 mL of solution.
[NaOH] = 1.04 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.0297 M
0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.
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Answer: It’s a bad conductor of electricity
Explanation:
