Answer:
- z direction
Explanation:
To find the direction of the magnetic field, you take into account that the magnetic force over a charge, is given by the following cross product:
(1)
F_B: magnetic force
q: charge of the particle
v: velocity of the charge
B: magnetic field
In this case you have that the electron is moving along x-axis. You can consider this direction as the ^i direction. The electron experiences a magnetic deflection in the -y direction, that is, in the -^j direction.
By the cross products between unit vectors, you have that:
-^j = ^i X ^k
That is, the cross product between two vectors, one in the +x direction, and another one in the +z direction, generates a vector in the -y direction. However, it is necessary to take into account that the negative charge of the electron change the sign of the result of the cross product, which demands that the second vector is in the -z direction. That is:
-^i X -k^ = ^i X ^k = - ^j
Hence, the direction of the magnetic field is in the -z direction
Answer: 8 years
Explanation:
According to Kepler’s Third Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”:</em>
<em />
(1)
In other words: this law states a relation between the orbital period of a body (moon, planet, satellite, comet, asteroid) orbiting a greater body in space (the Sun, for example) with the size of its orbit.
However, if is measured in years (Earth years), and is measured in astronomical units (equivalent to the distance between the Sun and the Earth: ), equation (1) becomes:
(2)
This means that now both sides of the equation are equal.
Knowing and isolating from (2):
(3)
(4)
Finally:
This is the period of the asteroid
Can you get a better pic so i can read it
Answer:
Work done = 4584.9 J
Explanation:
given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C
Solution:
Formula for the potential difference at the center of the circle
P.E = K × q1 q2 /r (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)
P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C / 0.20 m
P.E = 4584.9 J = Work done