Answer:
Explanation:
Using 
4.01 × 10^3 * 4.186 = 1.72×10^4j
In KJ 17.2kj
 
        
             
        
        
        
Fusion occurs in the Sun's core, releasing energy that is transferred outward. Once in the radiative zone, gamma rays are transferred by radiation. They are converted to other types of photons, which move into the convective zone, where they are transferred by convection. Finally, energy is emitted from the photosphere.
        
                    
             
        
        
        
Answer:
a). A conservative force permits a two-way conversion between kinetic and potential energies.
TRUE
Because there is no energy loss in presence of conservative forces so energy conversion in two ways are possible.
b). A potential energy function can be specified for a conservative force.
TRUE
negative gradient of potential energy is equal to conservative force

c). A non-conservative force permits a two-way conversion between kinetic and potential energies.
FALSE
here energy is lost against non-conservative forces
d). The work done by a conservative force depends on the path taken.
FALSE
work done by conservative force is independent of path
e). The work done by a non-conservative force depends on the path taken.
TRUE
work done by non conservative forces depends on path.
f). A potential energy function can be specified for a non-conservative force.
FALSE
It is not defined for non conservative forces
 
        
             
        
        
        
Answer:
MOMENTUM
Explanation:
another way of saying getting the smallest force possible is the word " MOMENTUM".
momentum is the ability to keep maintaining,incresing or itself developing to move at constant speed or to increase the speed.
 
        
             
        
        
        
Answer:
t = 5.59x10⁴ y
Explanation:
To calculate the time for the ¹⁴C drops to 1.02 decays/h, we need to use the next equation: 
 (1)
    (1)
<em>where  : is the number of decays with time, A₀: is the initial activity, λ: is the decay constant and t: is the time.</em>
: is the number of decays with time, A₀: is the initial activity, λ: is the decay constant and t: is the time.</em>
To find A₀ we can use the following equation:  
 (2)
   (2)
<em>where N₀: is the initial number of particles of ¹⁴C in the 1.03g of the trees carbon </em>
From equation (2), the N₀ of the ¹⁴C in the trees carbon can be calculated as follows:        
 
 
<em>where  : is the tree's carbon mass,
: is the tree's carbon mass,  : is the Avogadro's number and
: is the Avogadro's number and  : is the ¹²C mass.  </em>
: is the ¹²C mass.  </em>
 
    
Similarly, from equation (2) λ is:
 
 
<em>where t 1/2: is the half-life of ¹⁴C= 5700 years </em>

So, the initial activity A₀ is:   
 
     
Finally, we can calculate the time from equation (1):
 
               
I hope it helps you!