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3 years ago

Explain why the magnesium can be stretched to form magnesium ribbon...??

Chemistry

1 answer:

insens350 [35]3 years ago

3 0

Answer:

Because of its malleability.

Explanation:

Magnesium is alkaline earth metal.

It is present in second group.

It is shiny gray color metal.

It is lighter but strong.

Its density is 1.738 g/mL.

It is soft and can be malleable. Magnesium ribbons are also formed by stretching the magnesium metal and this is due to the malleability of magnesium.

Magnesium ribbon burns and produces heat.

It is used to make the many light weight products such as many parts of car, phone, laptop, luggage etc.

It is also used to remove the sulfur such as from iron and steel.

It is also used in fireworks.

It is also used in medicine such as for constipation.

It is used as antiacid for heart burn.

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How many molecules are in 2.00 moles of H20????????

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3 years ago

Read 2 more answers

1. Which of the following is a combination reaction?

DaniilM [7]

Answer:

The answer to your question is: letter A

Explanation:

A combination reaction is when there are two reactants that gives only one product.

a. 2SO2 + O2—> 2SO3 This is a combination reaction,

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3 years ago

If the concentration of phosphate in the cytosol is 2.0 mM and the concentration of phosphate in the surrounding fluid is 0.1 mM

Allushta [10]

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3 years ago

Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi

lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

Mass of water ,m= 1kg = 1000 g

Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

$q=-1.061^oC(1000 g\times 4.184J/g^oC+4.643 J/^oC )=-4,444.15J=-4.444 kJ$

Moles of propane = $\frac{1.860 g}{44 g/mol}=0.0422 mol$

0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

$\frac{4.444 kJ}{0.0422 mol}=105.308 kJ/mol$

3 0

3 years ago