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4 years ago

Explain why the magnesium can be stretched to form magnesium ribbon...??

Chemistry

1 answer:

insens350 [35]4 years ago

3 0

Answer:

Because of its malleability.

Explanation:

Magnesium is alkaline earth metal.

It is present in second group.

It is shiny gray color metal.

It is lighter but strong.

Its density is 1.738 g/mL.

It is soft and can be malleable. Magnesium ribbons are also formed by stretching the magnesium metal and this is due to the malleability of magnesium.

Magnesium ribbon burns and produces heat.

It is used to make the many light weight products such as many parts of car, phone, laptop, luggage etc.

It is also used to remove the sulfur such as from iron and steel.

It is also used in fireworks.

It is also used in medicine such as for constipation.

It is used as antiacid for heart burn.

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How many electrons are found in their outer shell ?

dezoksy [38]

The answer is eight electrons.

3 0

3 years ago

How many formula units are contained in 0.57 g Cao?

joja [24]

Then you will multiply the number of moles by 6.022×1023formula units/mol . To determine the molar mass of a compound, add the atomic weight on the periodic table in g/mol times each element's subscript. Since the formula unit CaO has no subscripts, they are understood to be 1

7 0

3 years ago

What type of reaction will occur with the following reactants?

zalisa [80]

Answer:

A) double replacement

Explanation:

Chemical equation:

NaCl +CaS → Na₂S + CaCl₂

Balanced chemical equation:

2NaCl +CaS → Na₂S + CaCl₂

The given reaction is double replacement reaction in which cation and anions of each reactant exchange with each other.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AD +CB

Other options are incorrect because,

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

AB → A + B

Single replacement:

It is the reaction in which one elements replace the other element in compound.

AB + C → AC + B

Decomposition reaction:

It is the reaction in which one reactant is break down into two or more product.

AB → A + B

6 0

3 years ago

Combustion analysis of 63.8 mg of a c, h and o containing compound produced 145.0 mg of co2 and 59.38 mg of h2o. what is the emp

Makovka662 [10]

<span>: The empirical formula for the compound is C3H60 (see below) CO2 is the only product containing C, C produced = 145.0 mg CO2 x (1 g / 1000 mg) x (1 mole CO2 / 44.0 g CO2) x (1 mole C / 1 mole CO2) = 0.00330 moles C. H2O is the only product containing H, H produced = 59.38 mg H2O x (1 g / 1000 mg) x (1 mole H2O / 18.0 g H2O) x (2 moles H / 1 mole H2O) = 0.00660 moles H. Oxygen is in both and the unknown reacts with oxygen(in the air) 0.00330 moles C x (12.0 g C / 1 mole C) = 0.0396 g C = 39.6 mg C 0.00660 moles H x (1.01 g H / 1 mole H) = 0.00667 g H = 6.7 mg H Because the unknown weighed 63.8 mg and consists off justC, H, and O, then mass O = g unknown - g C - g H = 63.8 mg - 39.6 mg - 6.7 mg = 17.5 mg = 0.0175 g 0.0175 g O x (1 mole O / 16.0 g O) = 0.00109 moles O The mole ratio of C:H:O is: C = 0.00330 H = 0.00660 O = 0.00109 Divide by the smallest you get: C = 0.00330 / 0.00109 = 3.03 H = 0.00660 / 0.00109 = 6.06 O = 0.00109 / 0.00109 = 1.00</span>

6 0

4 years ago

Determine the mass of ammonium chloride, NH4CI, required to prepare 0.250 L of a 0.35 M solution of ammonium chloride.

kkurt [141]

A 0.250 L solution of NH4Cl contains (0.250 L)(0.35 mol/L) = 0.0875 moles of dissolved NH4Cl. Converting this quantity to mass, we get (0.0875 mol NH4Cl)(53.491 g/mol) = 4.7 g NH4Cl (two significant figures).

So, approximately 4.7 g of NH4Cl dissolved in a 0.250 L solution will have a concentration of 0.35 L.

7 0

3 years ago