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Virty [35]
4 years ago
14

Explain why the magnesium can be stretched to form magnesium ribbon...??

Chemistry
1 answer:
insens350 [35]4 years ago
3 0

Answer:

Because of its malleability.

Explanation:

Magnesium is alkaline earth metal.

It is present in second group.

It is shiny gray color metal.

It is lighter but strong.

Its density is 1.738 g/mL.

It is soft and can be malleable. Magnesium ribbons are also formed by stretching the magnesium metal and this is due to the malleability of magnesium.

Magnesium ribbon burns and produces heat.

It is used to make the many light weight products such as many parts of car,  phone, laptop, luggage etc.

It is also used to remove the sulfur such as from iron and steel.

It is also used in fireworks.

It is also used in medicine such as for constipation.

It is used as antiacid for heart burn.

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3 years ago
In a healthy pond, the temperature is 16°C (61°F). What is the most likely pH of this pond?
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Answer:

A . 6.3 In a healthy pond, the temperature is 16°C (61°F). What is the most likely pH of this pond

7 0
3 years ago
If the density of an object is 5 g/cm3 and it takes up 7 cm3 of space, calculate the mass?
statuscvo [17]

Answer:

<h2>The answer is option A</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

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volume of object = 7 cm³

density = 5 g/cm³

The mass of the object is

mass = 5 × 7

We have the final answer as

<h2>35 g</h2>

Hope this helps you

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Read 2 more answers
Balancee las ecuaciones químicas por el método de tanteo e identifique que tipo de reacción es: 1.1.- Cloruro férrico acuoso rea
lakkis [162]

Respuesta:

2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)

Explicación:

Consideremos la ecuación no balanceada que ocurre cuando cloruro férrico acuoso reacciona con carbonato de sodio sólido para formar carbonato férrico sólido y cloruro de sodio acuoso. Esta es una reacción de doble desplazamiento.

FeCl₃(aq) + Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)

Vamos a usar el método de tanteo. Empezaremos balanceando los átomos de C, multiplicando Na₂CO₃ por 3.

FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)

Luego, balancearemos los átomos de Fe, multiplicando FeCl₃ por 2.

2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)

Finalmente, obtendremos la ecuación balanceada, multiplicando NaCl por 6.

2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)

4 0
3 years ago
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