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enot [183]
3 years ago
9

How many molecules are in 2L of water vapor at STP?

Chemistry
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

5.4 x 10²²molecules

Explanation:

Given parameters = 2L

Unknown; number of molecules

Condition of the water vapor is at standard Temperature and Pressure

Solution

To solve this problem, we simply find the number of moles the given volume would yield at STP using the relationship below:

             Number of moles = \frac{volume occupied}{22.4}

    Number of moles = \frac{2}{22.4} = 0.089mole

To find the number of molecules in the solved mole of the water vapor:

we use the avogadro's constant to evaluate.

             1 mole of a water vapor = 6.02 x 10²³ molecules

             0.089 mole of water vapor =  0.54 x 10²³molecules

Number of molecules of water is 5.4 x 10²²molecules

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Zigmanuir [339]

Answer:

the animal

Explanation:

a rodent thas in the ground

6 0
3 years ago
Can anyone give me the name of these? 40 points. Hope it's not too much
kolbaska11 [484]
1. 5 ethyl, 2 methyl octane
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4. 3,4-dimethyl hexene
5. 3,4-dimethyl cyclobutene
6. 3,5 diisopropyl cyclohexene
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8. 2,6 dibromo phenol

keep in mind that between 4-7, there could be #1 in front of the main name. for example with #4: 3,4-dimethyl-1- hexene. this honestly depends on the professor how he/she likes it. It is not necessary because if the number is not specified, it is assumed is #1
4 0
4 years ago
What quantity of heat is required to raise the temperature of 460g of aluminum from 15C to 85C?
Hoochie [10]

Answer:

Q = 28.9 kJ

Explanation:

Given that,

Mass of Aluminium, m = 460 g

Initial temperature, T_i=15^{\circ} C

Final temperature, T_f=85^{\circ}

We know that the specific heat of Aluminium is 0.9 J/g°C. The heat required to raise the temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=460\ g\times 0.9\ J/g^{\circ} C\times (85-15)^{\circ} C\\\\Q=28980\ J\\\\\text{or}\\\\Q=28.9\ kJ

So, 28.9 kJ of heat is required to raise the temperature.

6 0
3 years ago
What mass of potassium chloride, KCl, is produced when 12.6 g of oxygen, 02, is produced?
blagie [28]

Mass of KCl= 19.57 g

<h3>Further explanation</h3>

Given

12.6 g of Oxygen

Required

mass of KCl

Solution

Reaction

2KClO3 ⇒ 2KCl + 3O2

mol O2 :

= mass : MW

= 12.6 : 32 g/mol

= 0.39375

From the equation, mol KCl :

= 2/3 x mol O2

= 2/3 x 0.39375

=0.2625

Mass KCl :

= mol x MW

= 0.2625 x 74,5513 g/mol

= 19.57 g

4 0
3 years ago
A group of giraffes feeds on leaves and grasses during the daytime. Right now, it is dark out and the giraffes are not eating. I
Zanzabum

Answer:

Carbon dioxide is moving out of the living things.

Explanation:

The food materials eaten by living things contain carbon in the form of complex organic matter. When living things feed, they ingest this complex organic material into their bodies.

During the process of digestion, this complex organic material is broken down to give glucose. Glucose is the energy molecule in living things. Excess glucose in the body is stored as glycogen.

During cellular respiration, glucose is broken down to release carbon dioxide. Hence, at night when the giraffe has stopped eating, cellular respiration continues to occur and carbon dioxide is released, that is, carbon dioxide continues to move out of living things at night.

7 0
3 years ago
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