Answer:
The answer to the question is
Suki is 1.12 m close to the end of the steel beam before the beam begins to tip
Explanation:
To solve the question we list out the known variables first
Length of steel beam, L = 7.00 m
Weight of steal beam W = 326 N
Distance between supports = 3.00 m
Weight of Suki = 555 N
By moments theory, the sum of moments about a point = 0
and assuming the steal beam is uniform, the weight of the beam will act at the center of the beam
As described the supports are 2.00 m from each end of the beam thus
taking moments about one of the support with Suki between the end of the beam and the support we have
Distance from center of beam to support = 1.5 m
Distance of Suki to the nearest support = x m
therefore 555 × x + 326 × 1.5 = 0
or x = -0.881 m on the other side of the support
Therefore Suki is (2 - 0.881) m or 1.12 m close to the end before the beam begins to tip
Answer:
20.9%
Explanation:
I took the test i hope this helps:)
Answer:
Part A = The mass of sulfur is 6.228 grams
Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams
Explanation:
Part A
Step 1: Data given
A mixture of carbon and sulfur has a mass of 9.0 g
Mass of the product = 27.1 grams
X = mass carbon
Y = mass sulfur
x + y = 9.0 grams
x = 9.0 - y
x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6
(9 - y)*(44.01/12.01) + y(64.07/32.07)
(9-y)(3.664) + y(1.998)
32.976 - 3.664y + 1.998y = 22.6
-1.666y = -10.376
y = 6.228 = mass sulfur
x = 9.0 - 6.228 = 2.772 grams = mass C
The mass of sulfur is 6.228 grams
Part B
Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).
Calculate moles of 1 silver atom
Moles = 1/ 6.022*10^23
Moles = 1.66*10^-24 moles
Mass = moles * molar mass
Mass = 1.66*10 ^-24 moles *107.87
Mass = 1.79 * 10^-22 grams
The mass of 1 silver atom is 1.79 * 10^-22 grams
Answer : The concentration of NaOH is, 0.336 M
Explanation:
To calculate the concentration of base, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:


Thus, the concentration of NaOH is, 0.336 M
17 protons 17 electrons 18 neutrons