How many molecules are in 2L of water vapor at STP?
1 answer:
Answer:
5.4 x 10²²molecules
Explanation:
Given parameters = 2L
Unknown; number of molecules
Condition of the water vapor is at standard Temperature and Pressure
Solution
To solve this problem, we simply find the number of moles the given volume would yield at STP using the relationship below:
Number of moles =
Number of moles = = 0.089mole
To find the number of molecules in the solved mole of the water vapor:
we use the avogadro's constant to evaluate.
1 mole of a water vapor = 6.02 x 10²³ molecules
0.089 mole of water vapor = 0.54 x 10²³molecules
Number of molecules of water is 5.4 x 10²²molecules
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The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.
where,
- i: van 't Hoff factor (1 for non-electrolytes)
- Kf: cryoscopic constant
- m: molality
The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
Learn more: brainly.com/question/2292439