Question

How many grams of MgSO4 should Naomi weigh out to prepare 0.250 L of a 1.25 M solution?

Answer 1

Answer:

Mass of MgSO₄ = 37.61 g

Explanation:

Given data:

Mass of MgSO₄ needed = ?

Volume of solution = 0.250 L

Molarity of solution = 1.25 M

Solution:

Formula;

Molarity = number of moles of solute / L of solution

Now we will put the values in formula:

1.25 M = number of moles of solute / 0.250 L

Number of moles of solute = 1.25 M ×0.250 L

             (M = mol/L)

Number of moles of solute = 0.3125 mol

Mass = number of moles × molar mass

Mass = 0.3125 mol  × 120.366 g/mol

Mass = 37.61 g